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Marysya12 [62]
3 years ago
11

A car is traveling at a speed of 50 km/hr. The positive y-axis is north and the positive x-axis is east. Resolve the car's veloc

ity vector (in 2-space) into components if the car is traveling in each of the following directions:
east
south
southeast
northwest
Physics
1 answer:
hjlf3 years ago
6 0
We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.

hope this help
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If you throw an apple towards the sky why its going up in spite of gravitational pull? .
Paul [167]

Answer:

due to tension force acting against gravitational pull

Explanation:

hope this somewhat helps :)

4 0
3 years ago
Name on contact force and one field force acting on you right now
kati45 [8]

Answer:

Contact forces are forces that require the actual contact (touching) of two pieces of matter. There are a variety of contact forces. A very common one is friction. Anytime that two surfaces are in contact with one another, there is friction between the two surfaces. A field force is a force that works at a distance. No touching is required. Gravity is a good example of a field force, because it works whether or not an object is touching something or touching nothing at all.

8 0
3 years ago
A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a
Readme [11.4K]

Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

H = 4.905 m

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

a = g = 9.81 m/s^2

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

v_f = 0

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

\Delta y = 0 = v_y t + \frac{1}{2} at^2

0 = v_y (2) - \frac{1}{2}(9.81)(2^2)

v_y = 9.81 m/s

Part d)

at the maximum height position we know that the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a d

here we have

0 - (9.81^2) = 2(-9.81)H

H = 4.905 m

4 0
3 years ago
A vehicle travels from a 30m marker to a 100m marker. What is the change in distance
alexgriva [62]

70 meters is your answer

Note that the beginning is the 30 meter mark, and the ending is the 100 meter mark. Subtract the beginning amount from the end:

100 - 30 = 70

The vehicle traveled 70 meters.

~

8 0
3 years ago
How do you know that forces are balanced when static friction acts on an object?
lyudmila [28]
By looking at the acceleration of the object.
In fact, Netwon's second law states that the resultant of the forces acting on an object is equal to the product between the mass m of the object and its acceleration:
\sum F = ma

So, when static friction is acting on the object, if the object is still not moving we know that all the forces are balanced: in fact, since the object is stationary, its acceleration is zero, and so the resultant of the forces (left term in the formula) must be zero as well (i.e. the forces are balanced).
6 0
4 years ago
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