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Gre4nikov [31]
3 years ago
15

Markups The depth of water in a pond increases by 3% after a heavy rain. If the average depth of the water was 8.3 feet, what is

the new depth?​
Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer: 8.55 feet

Step-by-step explanation:

We should equal the average depth to 1, so if it raises 3%, it raises 0.03. Simply add the original (1) plus what it rose (0.03) and multiply the original by that, so 8.3 × 1.03 = new depth. The result is 8.549 feets.

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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Solve the following inequality for x. -5x&lt;-15x+40
melisa1 [442]

Answer:

x is less than 4

or

x is greater than 4

Step-by-step explanation:

-5x < -15x + 40 -5x < -15x + 40

+15x +15x -40 -40

10x < 40 -40 - 5x < -15x

÷10 ÷10 +5x +5x

× < 4 -40 < -10x

÷10 ÷10

4 < ×

5 0
3 years ago
Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f
Marrrta [24]

Answer:

\frac{48}{r+9}=\frac{12}{r}

Step-by-step explanation:

Let r represent Linda's walking rate.                      

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be t+9 miles per hour.

\text{Time}=\frac{\text{Distance}}{\text{Rate}}

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

\text{Time while riding}=\frac{48}{r+9}

\text{Time taken while walking}=\frac{12}{r}

Since both times are equal, so we will get:

\frac{48}{r+9}=\frac{12}{r}

Therefore, the equation \frac{48}{r+9}=\frac{12}{r} can be used to solve the rates for given problem.

Cross multiply:

48r=12r+108

48r-12r=12r-12r+108

36r=108

\frac{36r}{36}=\frac{108}{36}

r=3

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be t+9\Rightarrow 3+9=12 miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

7 0
3 years ago
My grade is 99% but I get a zero on a quiz that is 30% of my grade what is my grade
Gnom [1K]

Answer:69 percent

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
if 5 billion pennies are minted each year, how long would it take to mint the pennies needed to stack to the sun? pls show all w
kvasek [131]

Answer:

98 years

Step-by-step explanation:

because the sun is 432,690 miles

3 0
2 years ago
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