Its <span>234or238 hope dis helped</span>
Te limiting reagent from CS2 (g) + 3O2(g)---->CO2(g) +2SO2(g) is O2. It is defined as <span>the substance that is totally consumed when the chemical reaction is complete. The excess reagent is CS2.</span>
An Ionic Bond is a chemical bond that forms between non-metal, and metal ions through <span>electrostatic attraction.
A </span><span>Covalent bond is the sharing pair of of atoms and electrons.
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Metallic bond is a chemical bond between charecteristics of metals, where </span>mobile valence electrons are shared between atoms in a stable <span>crystalline.</span><span>
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Answer:
0.51M
Explanation:
Given parameters:
Initial volume of NaBr = 340mL
Initial molarity = 1.5M
Final volume = 1000mL
Unknown:
Final molarity = ?
Solution;
This is a dilution problem whereas the concentration of a compound changes from one to another.
In this kind of problem, we must establish that the number of moles still remains the same.
number of moles initially before diluting = number of moles after dilution
Number of moles = Molarity x volume
Let us find the number of moles;
Number of moles = initial volume x initial molarity
Convert mL to dm³;
1000mL = 1dm³
340mL gives
= 0.34dm³
Number of moles = initial volume x initial molarity = 0.34 x 1.5 = 0.51moles
Now to find the new molarity/concentration;
Final molarity =
=
= 0.51M
We can see a massive drop in molarity this is due to dilution of the initial concentration.
Explanation:
A substance that completely dissociates into ions when dissolved in its aqueous solution is known as a strong electrolyte.
Whereas a substance that does not dissociate into ions is known as a non-electrolyte.
If a substance partially dissociates into ions when dissolved in its aqueous solution then it is known as a weak electrolyte.
(a) ![A(l) \rightarrow A(aq)](https://tex.z-dn.net/?f=A%28l%29%20%5Crightarrow%20A%28aq%29)
As there is occurring no dissociation. Hence, no formation of ions takes place therefore, it is a non-electrolyte.
(b)
As partial dissociation of ions take place in this reaction as the reaction is in equilibrium state. Hence, it is a weak electrolyte.
(c) ![DE(aq) \rightarrow D^{+}(aq) + E^{-}(aq)](https://tex.z-dn.net/?f=DE%28aq%29%20%5Crightarrow%20D%5E%7B%2B%7D%28aq%29%20%2B%20E%5E%7B-%7D%28aq%29)
Here, complete dissociation of ions is taking place as the reaction is not in an equilibrium state. Therefore, it is a strong electrolyte.
(d) ![XY(s) \rightarrow X^{+}(aq)+Y^{-}(aq)](https://tex.z-dn.net/?f=XY%28s%29%20%5Crightarrow%20X%5E%7B%2B%7D%28aq%29%2BY%5E%7B-%7D%28aq%29)
Here also complete dissociation is taking place. Hence, it is a strong electrolyte.
(e) ![Z(s) \rightarrow Z(aq)](https://tex.z-dn.net/?f=Z%28s%29%20%5Crightarrow%20Z%28aq%29)
As there is occurring no dissociation. Hence, no formation of ions takes place therefore, it is a non-electrolyte.