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3 years ago

Will give brainiest please help find the arc.

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

6 0

Did you go to the link ? To find the answer

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Find m∠Y. Put the answer below.<br> m∠Y =

Dmitriy789 [7]

Answer:

60 degrees

Step-by-step explanation:

We are given the measures of WY and XY. Using them, we can find out 2WY=XY.

In 30-60-90 right triangle, the hypotenuse is 2 times the shortest leg. This means that this triangle is a 30-60-90 triangle. Angle Y is the angle made by the shorter leg and the hypotenuse therefore it is 60 degrees.

7 0

3 years ago

Read 2 more answers

What is the solution to the equation 3 − 4(2m + 6) + 3m = −16? (put number answers only)

NISA [10]

Answer:

1. -1

2.-4

3. 2

4.10

4 0

3 years ago

Complete the table.

Sauron [17]

Answer:

Step-by-step explanation:

20÷2=10

10×4=40

10×6=60

3 0

3 years ago

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Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$