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3 years ago

What is the common uses for Manganese??

Chemistry

1 answer:

White raven [17]3 years ago

7 0

I need help with this one too , can you guys please help us !!

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True or False - Elemental gases are relatively insoluble in water and should be given the state (g).

neonofarm [45]

Answer:

True

Explanation:

I assume this is refering to gases such as O2, H2, I2, F2, ect. And possibly the nobel gases which are completly insoluable. As gases they should be given the state (g).

3 0

3 years ago

Each of the identical volumetric flasks contains the same solution at two different temperatures. There are two identical volume

Montano1993 [528]

Explanation:

We know that molarity is the number of moles of solute present in liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

As molarity is dependent on volume and volume of a solution or substance is dependent on temperature. So, with increase in temperature there will occur a decrease in volume of the solution. As a result, molarity will increase as it is inversely proportional to volume.

Hence, molarity of both the solutions will be different as temperature of both the solutions is different.

8 0

4 years ago

How much heat in kilojoules is required to heat 56 l of water from 89 ∘f to 212 ∘f?

scoundrel [369]

You would need 67 if you add 56 and 89 = 145 and how i got 67. i went and subtract 212 and 145 = 67 and hope that answer you want if not well least i try

3 0

4 years ago

The pressure of a sample of gas is 500. mm Hg and the volume is 30.0 L. If the

Aloiza [94]

Answer: the new pressure will be 300mmHg

Explanation:

V1 = 30L.

V2 = 50L

P1 = 500mmHg

P2 =?

P1V1 = P2V2

30 x 500 = P2 x 50

P2 = (30 x 500) / 50

P2 = 300mmHg

6 0

4 years ago

In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)

Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.6 L

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}$

${V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L$

${V_2}=0.27\ L$

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0

4 years ago