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Varvara68 [4.7K]
2 years ago
15

N analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg sucrose.estimate the concentration of the resultant

solution in (i) mass percent (ii) degree brix
Chemistry
1 answer:
makvit [3.9K]2 years ago
5 0

The concentration of the solution in mass percent is 60%.

<h3>What is the mass percent?</h3>

The concentration of a substance can be expressed in mass percent. This refers to the percentage of the solute that is contained in the solution.

Thus we can write;

Mass percent = Mass of solute/ Mass of solution * 100/1

Mass percent = 1.5kg/1.5kg + 1 Kg * 100/1

Mass percent =  60%

Hence, the concentration of the solution in mass percent is 60%.

Learn more about mass percent:brainly.com/question/5394922

#SPJ1

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1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
3 years ago
Explain the difference between the strength of an acid and the concentration of an acid​
Alinara [238K]

Answer:

Hydrogen Fluoride will dissolve glass & eat concrete; BUT mixed with water, it is very nasty - but fairly weak!

A strong acid EASILY donates a Proton (H+).

Look up dissociation of acids and the ones that give up that H+ is the strong one.

Explanation:

6 0
3 years ago
What was the biggest challenge you faced in getting to where you are today and how did you overcome it?
Alchen [17]
It’s all based on you but yours could be anything hard you went through and how you overcame it. Also say how it made you the person you are today
4 0
3 years ago
At this temperature, 0.300 mol H 2 0.300 mol H2 and 0.300 mol I 2 0.300 mol I2 were placed in a 1.00 L container to react. What
Alekssandra [29.7K]

Answer:

The concentration of HI present at equilibrium is 0.471 M.

Explanation:

5 0
3 years ago
4.One rubber tire can generate about250,000 BTUS (1BTU=.0003KW ) when it is burned. The average American home consumes about 10,
jekas [21]

Answer:

The number of tires required to power ten homes for one year is approximately 2,730 tires

Explanation:

The given information are;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

The amount of energy consumed by the average American home = 10,000 kWh

Therefore, the amount of energy generated by burning one tire in kW can be found as follows;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

∴ 1 BTU × 250,000 = 250,000 BTUs = 0.0003 kW × 250,000 = 75 kW

We note that 250,000 BTUs is equivalent to 263764 kJ

1 kWh is equivalent to 3600 kJ

10,000 kWh = 10,000 × 3600 = 36,000,000 kJ

The energy requirement for ten homes  for one year = 10 × 36,000,000 kJ = 360,000,000 kJ

At 50% efficiency, the energy produced per tire = 0.5 × 263764 kJ = 131,882 kJ

The electrical energy produced per tire = 131,882 kJ/tire

The number of tires required to power ten homes for one year = 360,000,000 kJ/  131,882 kJ/tire = 2,729.71293  ≈2,730 tires

The number of tires required to power ten homes  ≈2,730 tires.

8 0
3 years ago
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