Answer:
All compounds are molecules
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Explanation:
It was similar because they both arranged the elements in order of increasing atomic mass.
Answer:
39.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction
Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)
Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH
The molar mass of CH₃COOH is 60.05 g/mol.
2.78 g × 1 mol/60.05 g = 0.0463 mol
Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH
The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.
Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂
0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL
Iron(III) sulfide is the name of the compound written using the Stock system. In the Stock system (named for Alfred Stock) a Roman numeral is used to indicate the oxidation number of the metal. Roman numerals are used in the names of compounds where the metal exhibits two or more oxidation states.
The sum of the oxidation states of a compound must always be zero. The oxidation state of sulfide is -2, and the oxidation state of sulfur, we are told by (III) is +3. You can either use the "criss-cross" trick to get the subscripts where the oxidation number of Fe becomes the subscript of S, and the oxidation number of S becomes the subscript of Fe...
+3-2
.FeS --> Fe2S3 .
Am 100% Sure The Best Answer..
Mole fraction of ethylene is = 0.144
How to find mole fraction ?
As, Given that vapor pressure = 7.88 torr
pure water vapor pressure = 9.21 torr
∆P solvent = (X Solute)(Pº solvent)
∆Psolvent = change in vapor pressure = 9.21 torr - 7.88 torr = 1.33 torr
Xsolute = mole fraction of the solute = ?
Pºsolvent = vapor pressure of the pure solvent = 9.21 torr
1.33 torr = (Xsolute)(9.21)
Xsolute = 1.33 torr/9.21 torr)
Xsolute = 0.144
Hence the mole fraction of ethylene is = 0.144
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