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Ket [755]
3 years ago
12

Precipitation reactions: Hg(NO3)2(aq) +Na2CrO4(aq) = _________ (aq) + NaNO3 (s)

Chemistry
1 answer:
valina [46]3 years ago
5 0
The completed and balanced equation is:
<span>Hg(N<span>O3</span><span>)2</span>+N<span>a2</span>Cr<span>O4</span>=HgCr<span>O4</span>+2Na(N<span>O3</span>)
Hope this helps :)</span>
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[H3O+] = 2.9 x 10-10 M<br> ph level
Zinaida [17]

Answer:

9.54

Explanation:

Fr the question given above, the following data were:

Concentration of hydronium ion [H3O⁺] = 2.9x10¯¹⁰ M

pH =?

The pH of the solution can be obtained as follow:

pH = –Log [H3O⁺]

pH = –Log 2.9x10¯¹⁰

pH = 9.54

Thus, the pH level of the solution is 9.54

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suppose the mass spectrum of a hypothetical monatomic element X contains a signal at mass number 13 and another of identical hei
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Average the numbers 13 and 15 to get 14amu.
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Explain why this substance is formed?
sveticcg [70]

Explanation:

About which substance you are talking?

6 0
2 years ago
How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th
OLEGan [10]

Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

<em>How much heat energy is required to convert 48.3 g of solid ethanol at -114.5°C to gaseous ethanol at 135.3 °C?</em>

<em />

We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

48.3g.\frac{1mol}{46.07g} =1.05mol

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

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What is the minimum amount of heat required to completely melt 20.0 grams of ice af it's melting point
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The answer is 6608J ..
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