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Ket [755]
3 years ago
12

Precipitation reactions: Hg(NO3)2(aq) +Na2CrO4(aq) = _________ (aq) + NaNO3 (s)

Chemistry
1 answer:
valina [46]3 years ago
5 0
The completed and balanced equation is:
<span>Hg(N<span>O3</span><span>)2</span>+N<span>a2</span>Cr<span>O4</span>=HgCr<span>O4</span>+2Na(N<span>O3</span>)
Hope this helps :)</span>
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Briefly describe the action of hardwater with soap​
morpeh [17]

Answer:

The correct answer is - hard water reacts to form the calcium or magnesium salt of the organic acid of the soap.

Explanation:

Soaps are made up of fatty acids or oils by treating with strong alkali and are salts of sodium and potassium. Hard water, on the other hand, has a high concentration of minerals in comparison to soft water. When hard water and soap are mixed together the salts of the minerals like Ca2+ and Mg2+ ions present in hard water react with fatty acids of the soap.

The sodium salts are changed to the salts of calcium and magnesium which are precipitated to an insoluble substance. The insoluble salts of the calcium or magnesium dirt stick on the clothes thus cleaning ability of soap is reduced.

4 0
2 years ago
What was the answer \
bearhunter [10]
What was the question?
4 0
3 years ago
Need help on this question asap pleasee
algol [13]

Answer:

9.0 moles of CaO

Explanation:

We have the reaction equation as follows;

Fe2O3 + Ca3(PO4)2 -------> 2FePO4 + 3CaO

Now we know from the equation that;

1 mole of iron III oxide yields 3 moles of CaO

Therefore;

3 moles of iron III oxide yields 3 * 3/1

= 9.0 moles of CaO

6 0
2 years ago
How would the world be different if people were not aware of radioactive decay
allsm [11]

Answer:

everyone would die

Explanation:

if we did not know about it we would not do anything about it

6 0
3 years ago
Draw all four products obtained when 2-ethyl-3-methyl-1,3-cyclohexadiene is treated with HBr at room temperature and show the me
LenKa [72]

Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

5 0
2 years ago
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