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Nataliya [291]
3 years ago
9

Experiment: finding absolute zero experimentally

Chemistry
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

When mensuration volume of air within the flask at the primary temperature, a volume of 250mil was recorded, referred to as V1. The temperature of the air within the flask in boiling water was recorded as 99ᵒC, referred to as T2. so as to seek out the right calculations, 99ᵒC must be born-again to Kelvin by adding 273.

the primary temperature in Kelvin is 372K. the worth of V1/T1, may be found by swing 250/372. This involves a complete of zero.67. the quantity of the air within the flask of the second temperature was 177 mil, referred to as V2.

The temperature of the air within the cooled flask is 7ᵒC, referred to as T2. 7ᵒC must be born-again to Kelvin by adding 273 that involves a final total of 280K. the worth of V2/T2, found by swing 177/280 involves a complete of zero.63.

The close to equality in numbers may be attributed to Charles Law. Charles Law states that “as the temperature will increase, thus will the quantity of a gas sample once the pressure is command constant”.

The results of V1/T1 and V2/T2 were terribly on the brink of one another. this can be because of the very fact that this experiment was worn out as a closed system. In Charles Law, if there's a closed system the 2 ratios ought to have equal numbers. {this is|this is often|this may be} why it can be expected for the magnitude relation numbers to be terribly equal.

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V₂ =279.4 cm³

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V₂ = 260 cm³ × 317k / 295k

V₂ = 82420 cm³. k  / 295k

V₂ =279.4 cm³

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