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Nataliya [291]
3 years ago
9

Experiment: finding absolute zero experimentally

Chemistry
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

When mensuration volume of air within the flask at the primary temperature, a volume of 250mil was recorded, referred to as V1. The temperature of the air within the flask in boiling water was recorded as 99ᵒC, referred to as T2. so as to seek out the right calculations, 99ᵒC must be born-again to Kelvin by adding 273.

the primary temperature in Kelvin is 372K. the worth of V1/T1, may be found by swing 250/372. This involves a complete of zero.67. the quantity of the air within the flask of the second temperature was 177 mil, referred to as V2.

The temperature of the air within the cooled flask is 7ᵒC, referred to as T2. 7ᵒC must be born-again to Kelvin by adding 273 that involves a final total of 280K. the worth of V2/T2, found by swing 177/280 involves a complete of zero.63.

The close to equality in numbers may be attributed to Charles Law. Charles Law states that “as the temperature will increase, thus will the quantity of a gas sample once the pressure is command constant”.

The results of V1/T1 and V2/T2 were terribly on the brink of one another. this can be because of the very fact that this experiment was worn out as a closed system. In Charles Law, if there's a closed system the 2 ratios ought to have equal numbers. {this is|this is often|this may be} why it can be expected for the magnitude relation numbers to be terribly equal.

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Suppose a sample of gas is composed of 100 molecules, with speeds given below. Speed (m/s) Number 200 23 400 42 600 26 800 8 100
ollegr [7]

Answer:

The answer is:

speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23  \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42  \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26  \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8  \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1  \\\\

Explanation:

Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.

Average speed for 1st option:

= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\  \frac{m}{s} \ \ \ \  \ \ \ \ \ \text{average speed of gas}

 Average speed for 2nd option:

 = \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}

 Average speed for 3rd option:

= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}

 Average speed for 4th option:

 = \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\  \frac{m}{s}

  Average speed for 5th option:

= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}

The average speed also increased by half because the temperatures had kinetic energy.\to 444 \ \frac{m}{s}\  to \ 222 \ \frac{m}{s}

7 0
3 years ago
PLEASE HELP ASAP <br> Half equation for zinc atoms changing into zinc ions
Yuri [45]

Answer:

Zn(s) -> Zn2+(aq) + 2e

Explanation:

Zinc atoms = no charge

Zinc ions = +ve charge

The process of half equation for zinc is called oxidation .

(oxidation means loss of electrons)

3 0
4 years ago
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balu736 [363]

Answer:

Prophase

Metaphase

Anaphase

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Explanation:

6 0
3 years ago
Ethanol is found to have a relative molecular mass of 46. If its molecular formula is C2HxOH. What is the value of X in the form
viva [34]

Answer:

The value of x in ethanol is 5

Explanation:

Given molar mass, you can subtract the molar masses of different elements present to find the missing amount of hydrogen; in other words:
Carbon*2 + Hydrogen*x + Oxygen*1 + Hydrogen*1 = 46
Molar mass carbon = 12.01
Molar mass hydrogen = 1
Molar mass oxygen = 16
12.01*2 g/mol + 1*x g/mol + 16*1 g/mol + 1*1 g/mol = 46 g/mol
Subtracting all knowns from the current molar mass gives
46 - 41.02 = 4.98

This means that x amounts of hydrogen has a molar mass of 4.98, or roughly just 5. Since each hydrogen has a molar mass of one, that means that there are 5 hydrogens missing and the complete molecular formula is C2H5OH

7 0
2 years ago
If you have 6 moles of reactant A and excess of B and C, how much product E would be formed? 3A+5B+1C=&gt;2D+1E
Black_prince [1.1K]
From the reaction you can state the molar ratios:

3 mol A : 5 mol B : 1 mol C : 2 mol D : 1 mol E.

Given that B and C are in excess, you know that reactant A is the limiting reactant, which means that is reacts completely. So, you can use the number of moles of reactant B to find how many moles of the products are produced.

For that, you build a proportion with the molar ratios between A and E,  and the number of moles of A that reacted:

=> 3 mol A / 1 mol E = 6 mol A / x => x = 6 mol A * 1 mol E / 3 mol A

=> x = 6*1/3 mol E = 2 mol E.

Answer: 2 moles of E.
5 0
3 years ago
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