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lorasvet [3.4K]
2 years ago
12

Ethanol is found to have a relative molecular mass of 46. If its molecular formula is C2HxOH. What is the value of X in the form

ula?
Chemistry
1 answer:
viva [34]2 years ago
7 0

Answer:

The value of x in ethanol is 5

Explanation:

Given molar mass, you can subtract the molar masses of different elements present to find the missing amount of hydrogen; in other words:
Carbon*2 + Hydrogen*x + Oxygen*1 + Hydrogen*1 = 46
Molar mass carbon = 12.01
Molar mass hydrogen = 1
Molar mass oxygen = 16
12.01*2 g/mol + 1*x g/mol + 16*1 g/mol + 1*1 g/mol = 46 g/mol
Subtracting all knowns from the current molar mass gives
46 - 41.02 = 4.98

This means that x amounts of hydrogen has a molar mass of 4.98, or roughly just 5. Since each hydrogen has a molar mass of one, that means that there are 5 hydrogens missing and the complete molecular formula is C2H5OH

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Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b
DIA [1.3K]
<h3>Answer:</h3>

Longest wavelength = 343.7 nm

<h3>Solution and Explanation:</h3>

In this question we need to first use the concept of energy of a photon.

Energy of a photon, E, is given by the formula, E = hf, where h is the plank's constant, f is the frequency.

But since, f is given by dividing speed, c, by wavelength, λ, then;

E = hc/λ

We are given 348 kJ/mol required to break carbon-carbon bonds.

We know that; 1 mole of bonds = 6.022 × 10^23 bonds.

We are required to find the longest wavelength with enough energy to break the C-C bonds.

This can be worked out in simple steps:

Step 1:  Energy required to break one bond (kJ/bond)

1 mole of bonds = 6.022 × 10^23 bonds.

Therefore;

348 kJ = 6.022 × 10^23 bonds.

Thus;

1 bond = 348 kJ ÷ 6.022 × 10^23 bonds.

           =  5.778 x 10^-22 kJ

But; 1000 joules = 1 kJ

Hence; energy per bond =  5.778 x 10^-19 Joules

Step 2: Energy per photon

Breaking one bond requires energy equivalent to energy of a photon.

Therefore;

1 photon = 5.778 x 10^-19 Joules

              = 5.778 x 10^-19 J/photon

Step 3: Calculating the wavelength

From the equation of energy of a photon;

E = hc/λ

h is the plank's constant = 6.626 × 10^-34 J/s

c is the speed of light in vacuum = 2.9998 × 10^8 m/s

E is the energy of a photon =  5.778 x 10^-19 Joules

Therefore, making λ (wavelength) the subject;

wavelength = \frac{hc}{E}

= \frac{(6.626 . 10^{-34})(92.9998.10^8) }{(5.778 .10^{-19} )}

= 3.437. 10^{-7} m

       = 3.437 x 10^-7 m

But; 1 nm = 10^-9 m

Thus;

wavelength = 343.7 nm

Therefore, the longest wavelength of the radiation will be 343.7 nm

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3 years ago
How many moles are present in a 120.0g sample of calcium
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4 0
3 years ago
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According to the wave-mechanical model of the atom, an orbital is a region of the most probable location of
Mademuasel [1]
With the advancement of science, electrons seemed to possess both particle and wave nature. 
this is called the dual nature where electrons have both particle and wave properties. 
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Later it was found that electrons do not have fixed positions, the exact momentum and position of electrons cannot be determined at the same time 
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3 years ago
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What is the oxidation number of cl in naclo3
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Let the unknow oxidation number b x
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8 0
3 years ago
Please help
Crank

Explanation:

Hello, let's observe the given data first. The data says The conc of magnesium chloride solution is 0.117 mol/L that means in one litre solution 0.117 mole MgCl2 are present. but we have to find the moles of magnesium chloride, magnesium ions & chloride ions in 16.4 mL solution.

\sf \: 1 \:  litre \:  solution  \rightarrow 0.117 \:  mole \: MgCl_2

\sf \: 16.4 \:  millitre \:  solution  \rightarrow 0.117 \times  \frac{16.4}{ {10}^{3} }  \:  mole \: MgCl_2 \\     \boxed{\sf 1.91 \times  {10}^{ - 3}  \: mole \: MgCl_2}

Now 16.4 ml solution contains 1.91× 10-³ magnesium chloride.

Before finding the amount of ions in solution let's have a look at dissociation of magnesium chloride.

MgCl_2 \rightarrow Mg^{2+} + 2Cl^{-}

<em>One mole of Magnesium chloride produces 1 mole of magnesium & 2 mole of chloride ions.</em>

Hence 1.91× 10-³ moles of magnesium chloride will produce 1.91 × 10-³ moles of magnesium ion & 3.82 × 10-³ moles of chloride ions.

\sf Thanks  \: for \:  joining \:  brainly  \: community!

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