Question

The strength of the electric field 0.5 m from a 6 µC charge is positive N/C. (Use k = 8.99 × 109 N• and round answer to the nearest whole number.)

Answer 1

Answer:

$2.16 \cdot 10^5 N/C$

Explanation:

The strength of the electric field produced by the single charge is given by

$E=\frac{kq}{r^2}$

where

$k=8.99\cdot 10^9 N m^2 C^{-2}$ is the Coulomb's constant

$q = 6 \mu C = 6 \cdot 10^{-6} C$ is the charge

$r = 0.5 m$ is the distance from the charge at which we want to calculate the field strength

Substituting the numbers into the equation, we find

$E=\frac{(8.99\cdot 10^9 )(6 \cdot 10^{-6} C)}{(0.5 m)^2}=2.16\cdot 10^5 N/C$

Answer 2

According to e2020 the answer is 215760