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3 years ago

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An arithmetic sequence has a common difference of 2 and contains the value 86 at some point in the sequence. Which of the follow

ing recursive formulas could represent this sequence?
Group of answer choices

an = an – 1 + 2; a1 = 1

an = an – 1 + 2; a1 = 2

an = an – 1 + 1; a1 = 2

an = an – 1 + 1; a1 = 1

1 answer:

shusha [124]3 years ago

3 0

Answer:

B. $a_{n} = a_{n-1}+2$ ; $a_{1} = 2$

Step-by-step explanation:

According to the statement, we find that the following two conditions must be observed:

$a_{i} = 86$ (Eq. 1)

$a_{i}-a_{i-1} = 2$ (Eq. 2)

Since the difference between two even numbers leads to another even number. Hence, $a_{1}$ must be an even number and the correct answer is B.

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Answer:

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Step-by-step explanation:

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4 years ago

Find the area of a trapezoid with bases 2ft and 3ft and height 1/3 foot. Round your answer to the nearest tenth

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Answer:

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Step-by-step explanation:

Formula

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Givens

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Solution

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3 years ago

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Answer:

1) True 2) False

Step-by-step explanation:

1) Given $\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$

To verify that the above equality is true or false:

Now find $\sum\limits_{k=0}^8\frac{1}{k+3}$

Expanding the summation we get

$\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3}$ $\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Now find $\sum\limits_{i=3}^{11}\frac{1}{i}$

Expanding the summation we get

$\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Comparing the two series we get,

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Verify the above equality is true or false

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Expanding the summation we get

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}$

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Expanding the summation we get

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Comparing the series we get that the given equality is false.

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Answer:

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Step-by-step explanation:

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