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madam [21]
3 years ago
10

An arithmetic sequence has a common difference of 2 and contains the value 86 at some point in the sequence. Which of the follow

ing recursive formulas could represent this sequence?
Group of answer choices

an = an – 1 + 2; a1 = 1

an = an – 1 + 2; a1 = 2

an = an – 1 + 1; a1 = 2

an = an – 1 + 1; a1 = 1
Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

B. a_{n} = a_{n-1}+2; a_{1} = 2

Step-by-step explanation:

According to the statement, we find that the following two conditions must be observed:

a_{i} = 86 (Eq. 1)

a_{i}-a_{i-1} = 2 (Eq. 2)

Since the difference between two even numbers leads to another even number. Hence, a_{1} must be an even number and the correct answer is B.

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Answer:

Left on the x-axis

Step-by-step explanation:

The opposite of the coefficient's amount of units is how much the graph will be moved.

Table comparisons

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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t
Arte-miy333 [17]

Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

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Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

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