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Maru [420]
2 years ago
11

PLEASE HELP!!

Chemistry
1 answer:
Ray Of Light [21]2 years ago
7 0
So that every measurement is accurate.. hope this helps
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Complete the sentence using ide, ate or Ic. To determine the name of an anion, you take the name of its element and replace the
lara31 [8.8K]

To determine the name of an anion, you take the name of its element and replace the end with "ide".

<h3>What is an anion?</h3>

An anion in chemistry is a negatively charged ion.

Anions are usually formed when a non-metallic atom gains electron(s).

An anion is usually named by taking the elemental name, removing the ending, and adding “ide.

Examples of anions are as follows:

  • fluoride (F-)
  • Chloride (Cl-)
  • Iodide (I-)

Learn more about anions at: brainly.com/question/15578817

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8 0
2 years ago
Which one of the following electron transitions does not correspond to an absorbtion of a quanta of light?
ziro4ka [17]
N = 4 to n = 3 is the right answer, so it' none of the above
8 0
3 years ago
Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = <u>144</u>

Now we can find percentage composition / percentage by mass of oxygen.

% composition = \frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound} × 100

% composition = \frac{144}{240.9} × 100 = <u>59.776%</u>

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0
2 years ago
Nucleic acids are chains of 5-carbon sugars linked by ____ bonds with an organic base protruding from each sugar.
Mekhanik [1.2K]
<span>B) phosphodiester </span> is the correct answer
3 0
3 years ago
You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem
Vlad [161]

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

<span>Cp = 1.36 J / g °C</span>

4 0
3 years ago
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