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scZoUnD [109]
3 years ago
11

Complete each nuclear fusion reaction.

Chemistry
2 answers:
Yuri [45]3 years ago
5 0

<u>Answer:</u> D represents 222, E represents 86, F represents 234 and G represents 90.

<u>Explanation:</u>

The two given chemical reactions are a type of alpha decay processes. Alpha decay process is defined as the process, in which a heavier nuclei decays into lighter nuclei emitting alpha particle. The alpha particle released has a charge of +2 units. and is also known as a helium nucleus.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}

The isotope formed has atomic mass reduced by 4 units and atomic number reduced by 2 units.

So, for the chemical equations:

1. _{226}^{86}\textrm{Ra}\rightarrow _{222}^{84}\textrm{Rn}+_2^4\textrm{He}

D represents 222, E represents 86.

2. _{238}^{92}\textrm{U}\rightarrow _{234}^{90}\textrm{Rn}+_2^4\textrm{He}

F represents 234 and G represents 90.

KatRina [158]3 years ago
5 0

Answer:

D 222, E 86, F 234 and G 90.

Explanation:

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IrinaK [193]

Answer:

hypothesis

Explanation:

a question that can be answered wity a hypothesis is a question a scientist can answer

5 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
Why is it dangerous to react sodium and potassium with dulute sulphuric acid?​
spin [16.1K]

Answer:

Because sodium and potassium are very reactive metals so they react explosively with HCL and H2SO4 evolving a large amount of heat.

Explanation:

5 0
3 years ago
Read 2 more answers
what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?​
Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0
3 years ago
Indicate what happens to the concentration of Pb2+ in each half cell
Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

Electrons will flow from Left to Right direction.

3 0
3 years ago
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