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2 years ago

what is the boiling point of a 0.321 m aqueous solution of NaCl. Enter your rounded answer with 3 decimal places.

Chemistry

2 answers:

Tom [10]2 years ago

7 0

Answer:

∆T = imK

∆T = Change in boiling point (B.P.)

i = van't Hoff factor = 2 for NaCl (Na+ and Cl2_

m = molality = 0.321 m

k = boiling point constant for water = 0.512 deg/m

∆T = (2)(0.321)(0.512) = 0.329 degrees

Since the normal B.P. for water is 100ºC, the new boiling point of this solution is 100 + 0.329 = 100.329ºC

So Our Answer is 100.329ºC

Ronch [10]2 years ago

3 0

Answer:

I believe the rounded place is 100.333.

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Calculate the feed ratio of adipic acid and hexamethylene diamine that should be employed to obtain a polyamide of approximately

artcher [175]

Answer:

r= 0.9949 (For 15,000)

r=0.995 (For 19,000)

Explanation:

We know that

Molecular weight of hexamethylene diamine = 116.21 g/mol

Molecular weight of adipic acid = 146.14 g/mol

Molecular weight of water = 18.016 g/mol

As we know that when adipic acid and hexamethylene diamine react then nylon 6, 6 comes out as the final product and release 2 molecule of water.

$M_{repeat}=146.14+166.21-2\times 18.106\ g/mol$

$M_{repeat}=226.32\ g/mol$

Mo= 226.32/2 =113.16 g/mol

$M_n=X_nM_o$

Given that

Mn= 15,000 g/mol

15,000 = Xn x 113.16

Xn = 132.55

Now by using Carothers equation we know that

$X_n=\dfrac{1+r}{1+r-2rp}$

$132.55=\dfrac{1+r}{1+r-2\times 0.99r}$

By calculating we get

r= 0.9949

For 19,000

19,000 = Xn x 113.16

Xn = 167.99

By calculating in same process given above we get

r=0.995

3 0

3 years ago

Olive oil has a density of 0.92 g/mL. How much would 1 liter of olive oil weigh in grams?

svp [43]

Dimension analysis is to be used to solve this problem. First convert 1L to milliliters. That is equivalent to 1000 ml. Then by dimension analysis, multiply the volume ( 1000ml) to the density of oil (0.92 g/ml) resulting to the answer: 920 grams.

4 0

2 years ago

How is chemical bonding useful to our lives?

-BARSIC- [3]

Answer:

Three types of chemical bonds are important in human physiology, because they hold together substances that are used by the body for critical aspects of homeostasis, signaling, and energy production, to name just a few important processes. These are ionic bonds, covalent bonds, and hydrogen bonds.

Explanation:

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2 years ago

Phosphorus-32 (32P) is an isotope that is commonly used for medical and biological research. Phosphorus-32 has a half-life of 14

Pachacha [2.7K]

The activity of the sample when it was shipped from the manufacturer is 4.54 mCi

<h3>How to determine the number of half-lives that has elapsed </h3>

From the question given above, the following data were obtained:

Time (t) = 48 hours
Half-life (t½) = 14.28 days = 14.28 × 24 = 342.72 hours
Number of half-lives (n) =?

n = t / t½

n = 48 / 342.72

n = 0.14

<h3>How to determine the activity of the sample during shipping </h3>

Number of half-lives (n) = 0.14
Original activity (N₀) = 5.0 mCi
Activity remaining (N) =?

N = N₀ / 2ⁿ

N = 5 / 2^0.14

N = 4.54 mCi

Thus, the activity of the sample during shipping is 4.54 mCi

Learn more about half life:

brainly.com/question/2674699

5 0

2 years ago

Vanadium (II) oxide with Iron (III) oxide results in Vanadium (V) oxide and Iron (II) oxide. Balance this equation

evablogger [386]

Answer:

2VO + 3Fe2O3 —> V2O5 + 6FeO

Explanation:

The skeletal equation for the reaction is given below below:

VO + Fe2O3 —> V2O5 + FeO

We can balance the equation above by doing the following:

There are 2 atoms of V on the right side and 1 atom on the left side. It can be balance by putting 2 in front of VO as shown below:

2VO + Fe2O3 —> V2O5 + FeO

Now, we have a total of 5 atoms of O on the left and 6 atoms on the right side. We can balance it by putting 3 in front of Fe2O3 and 6 in front of FeO as shown below:

2VO + 3Fe2O3 —> V2O5 + 6FeO

Now, we can see that the equation is balanced

4 0

2 years ago