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natita [175]
2 years ago
5

What is the mass of ethane at STP with a density of 2.1 g/L.

Chemistry
1 answer:
inessss [21]2 years ago
4 0

Answer:

i d k

Explanation:

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When metals, non metals,and metallics are composed according to luster, which is best description of the appearance of metalloid
Nitella [24]

Answer:

Metalloids are metallic-looking brittle solids that are either semiconductors or exist in semiconducting forms, and have amphoteric or weakly acidic oxides. Typical nonmetals have a dull, coloured or colourless appearance; are brittle when solid; are poor conductors of heat and electricity; and have acidic oxides.

Explanation:

5 0
2 years ago
A liquid has a _____.
guajiro [1.7K]

Answer:

definite volume

Explanation:

hope this helps!❆

3 0
2 years ago
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An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi
yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃     +    2HCl   =   CaCl₂  +  CO₂  +  H₂O .

1 mole        2 moles

2 moles of HCl reacts with 1 mole of  CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of  CaCO₃

CaCO₃ reacted with HCl =  .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0
2 years ago
Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the followi
Nitella [24]

Answer:

126.4 g of C_{4}H_{10} are required

Explanation:

Balanced reaction: 2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O

According to balanced reaction-

8 moles of CO_{2} are produced from 2 moles of C_{4}H_{10}

So, 8.70 moles of CO_{2} are produced from (\frac{2}{8}\times 8.70) moles of C_{4}H_{10} or 2.175 moles of C_{4}H_{10}

Molar mass of C_{4}H_{10} = 58.12 g/mol

So, mass of C_{4}H_{10} required = (2.175\times 58.12)g = 126.4 g

Hence 126.4 g of C_{4}H_{10} are required

5 0
3 years ago
Is 4 grams of oxygen bigger than 1 mole of oxygen
levacccp [35]

Answer:

No, a mole of oxygen is about 16 grams

Explanation:

6 0
3 years ago
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