All categories

3 years ago

How does radiocarbon (or uranium) dating help us better understand the world

Chemistry

1 answer:

navik [9.2K]3 years ago

4 0

Here we have to discuss the understanding of world through radiocarbon or uranium.

The radiocarbon or uranium helps us to determine the age of the world.

All uranium or radiocarbon elements after ejecting the radioactive rays convert to non-radioactive element lead (²⁰⁸Pb). If we assume that during the generation of world there were not any amount of lead was present i.e. only uranium or radiocarbon was present. Then by analysis of any uranium or radiocarbon at the present date one can determine the age of the world as follows:

In present moment we know that the ratio of uranium (U) and lead (Pb) in any uranium ore is 10:3 (gram atom ratio)

So, $\frac{the amount of uranium at the generation of world}{The remaining amount of uranium on present day}$ = $\frac{10+3}{10}$

Therefore, from the equation: ln $\frac{N_{0} }{N}$ = λt (where λ = rate of dissociation of uranium, t = time); we can write:

t = λ⁻¹ ln $\frac{N_{0} }{N}$ = λ⁻¹ln $\frac{13}{10}$ .

On plugging the dissociation rate of uranium we can obtain the age of the world, which is nearly 1.5×10⁹ years.

Thus the use of radioactive element to understand the world is explained.

You might be interested in

Atoms of arsenic (As) are often added to silicon (Si) in a process called doping to change the conductivity of the silicon. How

Basile [38]

Answer:

B.) An atom of arsenic has one more valence electron and more electron shells than an atom of silicon, so the conductivity decreases because the arsenic atom loses the electron.

Explanation:

Silicon is located in the 3rd row and 14th column in the periodic table. Arsenic is located in the 4th row and 15th column in the periodic table. This means that arsenic has one more valence electron than silicon. Since arsenic is located one row down from silicon, its valence electrons occupy higher energy orbitals.

Silicon maintains a crystal-like lattice structure. Each silicon atom is covalently connected to assume this shape. When silicon gains one extra electron from arsenic, it experiences n-type doping. This new electron is not tightly bound in the lattice structure. This allows it to move more freely and conduct more electricity. This can also be explained using band gaps. Silicon, which previously had an empty conduction band, now has one electron in this band. This lowers the band gap between the conduction and valence bands and increases conductivity.

5 0

2 years ago

How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?

timama [110]

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

Thus, the amount of the radioactive isotope remaing is the 100 g.

3 0

2 years ago

Which of the following is a compound?<br> a. iron<br> b. lead<br> c. helium<br> d. methane

Lana71 [14]

The correct answer is d) methane ( $CH_4$ )

The other options are elements.

6 0

3 years ago

Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a d ensity of 16.6 g/cm3, and an atomic

Sidana [21]

solution:

$Ta is BCC, a=\frac{4}{\sqrt{3}r},n=2atoms/cell\\p=16.6gram/cm^3,A=180.9gram/mol\\P=\frac{A\times n}{N_{a}\times v}=\frac{180.9\frac{gram}{mol}\times 2 \frac{atom}{cell}}{6.023\times10^23\frac{atom}{mol}\times(\frac{4}{\sqrt{3}\times r})^3\frac{cm^3}{cell}}\\=16.6\frac{gram}{cm^3}\\r=(\frac{180.9\times2}{16.6\times6.023\times10^23\times(\frac{4}{\sqrt{3}})^3})^\frac{1}{3}\times10^8$

4 0

3 years ago

Pleaseee helpppp!!!!!!!!

Katarina [22]

Answer:

a covalent would be the two that are nonmetals

7 0

3 years ago