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2 years ago

5

ASAP

1 answer:

GenaCL600 [577]2 years ago

7 0

Answer:

Increasing pressure shifts rxn right (lower molar volume side of equation).

Explanation:

In general, if a stress is applied to a gas phase reaction, the reaction will shift away from the applied stress and establish a new equilibrium for the given reaction. The applied stress factors include ...

changes in masses of reactant or product,

changes in applied temperature values, and/or

changes in applied pressure values for a reaction confined in a reaction vessel.

For this problem, if pressure is increased on the reaction N₂(g) + 3H₂(g) ⇄ 2NH₃(g), the reaction will shift away from the applied stress, that is, in the direction of the product side of the reaction in order to relieve the applied stress as there are fewer number of moles of gas on the product side of the equation.

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olga2289 [7]

Answer: 1.67 kg

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $4.31\times 10^1kJ$ = $43100J$ (1kJ=1000J)

m= mass of substance = ?

c = specific heat capacity = $0.385J/g^0C$

Change in temperature , $\Delta T=T_f-T_i=6.71\times 10^1^0C=67.1^0C$

Putting in the values, we get:

$43100J=m\times 0.385J/g^0C\times 67.1^0C$

$m=1670g=1.67kg$ (1kg=1000g)

Thus the mass (in kg) of the copper sample is 1.67

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3 years ago

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grandymaker [24]

Answer: The specific heat of the unknown metal is $0.897J/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $5040$ Joules

m= mass of substance = 86.8 g

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Initial temperature of the water = $T_i$

Final temperature of the water = $T_f$

Change in temperature , $\Delta T=T_f-T_i=(64.7)^0C$

Putting in the values, we get:

$5040=86.8\times c\times 64.7^0C$

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The specific heat of the unknown metal is $0.897J/g^0C$

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