Answer:
2.06 m/s
Explanation:
From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.
Momentum before collision
Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5
Momentum after collision
The momentum after collision will be given by (9+27)*0.9=32.4
Relating the two then 9v+13.5=32.4
9v=18.5
V=2.055555555555555555555555555555555555555 m/s
Rounded off, v is approximately 2.06 m/s
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert<span> small force on the wall The </span>pressure exerted<span> by the </span>gas<span> is due to the sum of all these collision forces.The more particles that hit the walls, the higher the </span>pressure<span>.</span>
Explanation:
This is true because at maximum height, the velocity is 0
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Answer:
15"
Explanation:
Let x be the length of the longer part, then the length of the shorter part is 3x/5, or also x - 6
therefore we have the following equation:
3x/5 = x - 6
We can multiply both sides by 5
3x = 5x - 6*5
2x = 30
x = 30/2 = 15"
So the length of the longer part is 15"