A change in position with respect to a reference point is called?

A cube has a drag coefficient of 0.8. What would be the terminal velocity of a sugar cube 1 cm on a side in air ( = 1.2 kg/mº)?

anzhelika [568]

0.495 m/s

Explanation

the formula for the terminal velocity is given by:

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ \text{where} \\ \end{gathered}$

m is the mass

g is 9.81 m/s²

ρ is density

A is area

C is the drag coefficient

then

Step 1

Let's find the mass

$\begin{gathered} \sigma=\frac{m}{v} \\ m=\sigma\cdot v \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(0.01m)^3 \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(1\cdot10^{-6}) \\ \text{mass}=2\cdot10^{-3}\operatorname{kg} \\ \text{mass}=0.002\text{ kg } \\ \text{Area}=(0.01\text{ m}\cdot0.01m)=0.0001m^2 \end{gathered}$

now, replace

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ v=\sqrt[]{\frac{2(0.002kg)(9.81\text{ }\frac{m}{s^2})}{(2\cdot10^3\frac{\operatorname{kg}}{m^3})(0.0001m^2)0.8}} \\ v=\sqrt[]{\frac{0.03924\frac{\operatorname{kg}m}{s^2}}{0.16\frac{\operatorname{kg}}{m^{}}}} \\ v=\sqrt[]{0.2452\frac{m^2}{s^2}} \\ v=0.495\text{ m/s} \end{gathered}$

hence, the answer is 0.495 m/s

3 0

1 year ago

You're conducting a physics experiment on another planet. You drop a rock from a height of 2.1 m and it hits the ground 0.6 seco

umka21 [38]

The formula to use is the one that connects the acceleration,
the distance fallen, and the time spent falling:

   Distance = 1/2 a T² .

You said 2.1 meters in 0.6 second .

   2.1 m       = 1/2 a (0.6 sec)²

Multiply each side by 2 :       4.2 m =    a (0.6 sec)²

Divide each side by (0.6 sec)² =    (4.2/0.36) m/s² = a

   a = (11 and 2/3) m/s²

(about 19% more than Earth's gravity)

3 0

3 years ago

Read 2 more answers

Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *

Sloan [31]

Answer:

Choice a. Approximately $0.83\; \rm A$ on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size $Q$ flowed through a wire cross-section over a period of time $t$ . The average current in that wire would be:

$\displaystyle I = \frac{Q}{t}$ .

For this question:

$Q = 500\; \rm C$ , whereas
$t = 10\; \rm \text{minutes}$ .

Therefore, the average current in this circuit would be:

$\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}$ .

However, the units in the choices are all in $\rm A$ (for Amperes.) One Ampere is equal to one $\rm C / \text{second}$ . It will take some unit conversations to change the unit of $I = 50\; \rm C/ \text{minute}$ (coulombs-per-minute) to coulombs-per-second.

$\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}$ .

Hence, the most accurate choice here would be choice a.

7 0

3 years ago

PLEASE HELP ASAP EXPLAIN PLEASE

Citrus2011 [14]

Answer:

How can smoking affect the respiratory system?

Smoking and Respiratory Disease

Smoking can cause lung disease by damaging your airways and the small air sacs (alveoli) found in your lungs. Lung diseases caused by smoking include COPD, which includes emphysema and chronic bronchitis. Cigarette smoking causes most cases of lung cancer.

Explanation:

4 0

3 years ago

Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.

LiRa [457]

Answer:

Explanation:

Given:

A = 589 J

D = 1 100 m

____________

F - ?

A = F·D

F = A / D = 589 / 1100 ≈ 0.54 N

5 0

1 year ago