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ira [324]
3 years ago
12

A change in position with respect to a reference point is called?

Physics
1 answer:
kumpel [21]3 years ago
4 0
A change in position with respect to a reference point is called motion

hope it helps...
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Are you an antisocial person. Me honestly am
gregori [183]

Explanation:

By the way.. What's the meaning of ANTISOCIAL??..(ㆁωㆁ)

If you tell me the meaning of it, I'll tell you my answer too(ㆁωㆁ)

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An experiment is designed to see if sleep affects the number of vocabulary words subjects can remember. The dependent variable i
Kaylis [27]

The dependent variable is: <em>"number of vocabulary words subjects can remember"</em>

<h3>Which is the dependent variable?</h3>

In an experiment, we basically see how changing one variable affects another variable.

In this case, the experiment is:

<em>" if sleep affects the number of vocabulary words subjects can remember."</em>

Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).

So the correct answer is:

<em>"number of vocabulary words subjects can remember"</em>

If you want to learn more about variables:

brainly.com/question/15246027

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7 0
2 years ago
An 800 N box is pushed across a level floor for a distance of 5.0 m with a force of 400 N. How much work was done on this box.
AveGali [126]

Answer: 2000 J.

Explanation: Since work is force*displacement, we just have to multiply the force by the distance: w = f*d = 400 N*5.0 m = 2000 J.

4 0
3 years ago
The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)
zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

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3 years ago
What is the pigment in the leaves called?
Angelina_Jolie [31]

Answer: D: Chloroplasts

Explanation:

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3 years ago
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