Answer:
a) 
, b) 
, c) 
, d) 
Explanation:
a) The angular velocity of the turntable after 
.
b) The change in angular position is:
c) The tangential speed of a point on the rim of the turn-table:
d) The tangential and normal components of the acceleration of the turn-table:
![a_{n} = (0.365\times 10^{-3}\,m)\cdot \left[(0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )\right]^{2}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20%280.365%5Ctimes%2010%5E%7B-3%7D%5C%2Cm%29%5Ccdot%20%5Cleft%5B%280.421%5C%2C%5Cfrac%7Brev%7D%7Bs%7D%20%29%5Ccdot%20%28%5Cfrac%7B2%5Cpi%5C%2Crad%7D%7B1%5C%2Crev%7D%20%29%5Cright%5D%5E%7B2%7D)
The magnitude of the resultant acceleration is:
Answer:
No
Explanation:
constant velocity means zero acceleration because acceleration is rate of change of velocity. So when velocity remains constant there would be no acceleration.
in case of constant acceleration it means that velocity changes but with some consistent (same) amount each time. For example some object falling from tower, Velocity of the object will change(increases) by 9.8m/s for each second due to gravity of Earth. In this case there is change in velocity each second but with some consistent amount that is 9.8m/s.
The answer is D, it increases the susceptibility to infections.
Umm do u want me to answer this’ll
Answer:
0.532
Explanation:
Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ
First, find your variables.
λ = 580 · 10^-9
d = 0.000125
m = 2
Next, fill in the equation.
d sin (θ) = m λ
(0.000125) sin (θ) = (2) (580·10^-9)
Then isolate your variable.
θ = arcsin ( (2)(580·10^-9) / (0.000125) )
Run your equation and you will end up with 0.53171246 , which rounds to 0.532.
The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.
I hope this helps :D
