Answer:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in 
which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Explanation:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
⇄ 
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Answer: Ammonia (NH3) and sodium carbonate (Na2CO3), because they accept hydrogen ions but lack hydroxide ions.
Explanation:
i took the test and got it correct :) hope this helps
<u>Answer:</u> The molarity of HCl solution is 0.262 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of HCl = 0.3366 g
Molar mass of HCl = 36.5 g/mol
Volume of the solution = 35.23 mL
Putting values in above equation, we get:
Hence, the molarity of HCl solution is 0.262 M.
Answer:
B
Explanation:
Particles in a solid have fixed locations in a volume that does not change. Solids have a definite volume and shape because particles in a solid vibrate around fixed locations.
The volume occupied by 0.102 mole of the helium gas is 2.69 L
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Number of mole (n) = 0.102 moles
- Pressure (P) = 0.95 atm
- Temperature (T) = 305 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) =?
<h3>How to determine the volume </h3>
The volume of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both sides by P
V = nRT / P
V = (0.102 × 0.0821 × 305) / 0.95
V = 2.69 L
Thus, the volume of the gas is 2.69 L
Learn more about ideal gas equation:
brainly.com/question/4147359
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