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Kay [80]
2 years ago
13

What kind of information does this map show?

Chemistry
2 answers:
jeka57 [31]2 years ago
7 0
A. This map shows only maps, so only logical one :)
Dmitry_Shevchenko [17]2 years ago
3 0
A the numbers represent highways.
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What is chemistry????????????????
labwork [276]
Chemistry is the branch of science that deals with the identification of the substances of which matter is composed the investigation of their properties and the ways in which they interact, combine, and change and the use of these processes to form new substances.
8 0
3 years ago
Read 2 more answers
Use your understanding of the terms "soluble" and "insoluble" to explain why you must shake a bottle of salad dressing made with
tekilochka [14]

Answer:

See explanation

Explanation:

In chemistry, the idea of "like dissolves like" is of utmost importance. A substance is only soluble in another with which it can effectively interact.

We must note that to be "soluble" means that the solute actually interacts effectively (dissolves) in the solvent.

However, vinegar is a polar substance while oil is a non polar substance hence the two can not effectively interact. That is, the vinegar can not dissolve in oil.

The two will separate into two phases upon standing. Therefore, the bottle of salad dressing made with oil and vinegar must be shaken in order to mix the two thoroughly before it is used.

6 0
3 years ago
Calculate the number of moles 3.16 g of KMnO4 32.33 g of K2CrO4 100 g of KHCO3
kvasek [131]
The number of moles:
3.16g of KMnO_{4}
1 mole of KMnO_{4}- 158g.
x moles of KMnO_{4}- 3.16g.
x=\frac{1\ mole*3.16g}{158g}=\frac{3.16}{158}=0.02\ mole

The number of moles:
32.33g of K_{2}CrO_{4}
1 mole of K_{2}CrO_{4}- 194g.
x moles of K_{2}CrO_{4}- 32.33g.
x=\frac{1\ mole*32.33g}{194g}=\frac{32.33}{194}=0.17\ mole

The number of moles:
100g of KHCO_{3}
1 mole of KHCO_{3}- 100.1g.
x moles of KHCO_{3}- 100g.
x=\frac{1\ mole*100g}{100.1g}=\frac{100}{100.1}=0.999\ mole


Greetings, 
n00nst00p :)
3 0
2 years ago
A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by a
julia-pushkina [17]

Answer:

0.170 M

Explanation:

As this is a <em>series of dilutions</em>, we can continuosly<em> use the C₁V₁=C₂V₂ formula </em>to solve this problem:

For the first step:

  • 59.0 mL * 1.80 M = 258 mL * C₂
  • C₂ = 0.412 M

Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:

  • V₂ = 129 mL + 183 mL = 312 mL

Using <em>C₁V₁=C₂V₂:</em>

  • 129 mL * 0.412 M = 312 mL * C₂
  • C₂ = 0.170 M
4 0
3 years ago
A 30.5 gram sample of glucose (c6h12o6) contains ________ atoms of oxygen.
Margaret [11]
First, find the number of moles of glucose in 30.5 g.

You need the molar mass.

Molar mass of C6H12O6 = 6 * 12.01 g/mol + 12 * 1.01 g/mol + 6*16g/mol = 180.2 g/mol

number of moles = mass in grams / molar mass = 30.5 g / 180.2 g/mol = 0.169 mol

Second, use molecular formula

1 mol of C6H12O6 contains 6 moles of O.

Then, 0.169 moles of C6H12O6 contains 6 *0.169 = 1.014 moles of O.

Third, multiply by Avogagro's number:

1.014 moles * 6.022 * 10^23 atoms / mole = 6.106 * 10^ 23 atoms.

Answer: 6.106 * 10 ^23 atoms of oxygen.
8 0
3 years ago
Read 2 more answers
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