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musickatia [10]

3 years ago

6

What is the area of a parallelogram that has a base of 412 in. and a height of 214 in.?

2 answers:

Talja [164]3 years ago

7 0

Answer:

area = 88,168 in²

Step-by-step explanation:

area = 412 x 214 = 88,168 in²

antoniya [11.8K]3 years ago

4 0

Answer:

88168in²

Step-by-step explanation:

:)

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posledela

$(k-2)(k-6)=k^2-2k-6k+12=k^2-8k+12$

So in order to get all the fractions to have a common denominator, we need to multiply $\dfrac k{k-2}$ by $\dfrac{k-6}{k-6}$ , and $\dfrac1{k-6}$ by $\dfrac{k-2}{k-2}$ :

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