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2 years ago

Which of these angles are the alternate interior angles theorem?

Mathematics

1 answer:

sleet_krkn [62]2 years ago

6 0

Answer:

C. ECA = BDA

Step-by-step explanation:

An angle is said to be produced whenever two or more lines meet at a point. An interior angle is an angle form within two lines meeting at a point. Then, alternate interior angles are internal angles that are equal due to alternate theorem. These angles should have equal measures.

From the given question, the alternate interior angles by the theorem is;

ECA = BDA

By the alternate interior angle theorem, the alternate interior angles are ECA and BDA. This implies that the measure of <ECA should be equal to the measure of <BDA.

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A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0

3 years ago

A line parallel to the graph of 3x+2y=6 and contains the point (6,-3)

FromTheMoon [43]

The Equation of the Line that Passes through (4, 2) and is Parallel to 3x – 2y = –6 is 3x – 2y = 8

5 0

2 years ago

Triunghiul si elementele lui Geometrie Clasa a -7 ex.11 p.154

Diano4ka-milaya [45]

que debería haber escrito sólo el problema para nosotros tal vez podríamos haber ayudado a continuación .

6 0

3 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago

Find the percent decrease. Round to the nearest percent. From 90°F to 70°F

Goryan [66]

Answer:

Step-by-step explanation:

90*x = 70

x = 7/9

x = 78%

100-78 = 22

3 0

2 years ago