1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Colt1911 [192]
3 years ago
11

If it continues to the snow rate of 4 inches every 2 hours

Mathematics
1 answer:
Ksju [112]3 years ago
6 0

Answer:

13

Step-by-step explanation:

You might be interested in
Simplify 16-4 [3+2÷(9-7)
elena-14-01-66 [18.8K]
16 - 4 [ 3 + 2 / (9 - 7)]
16 - 4 [ 3 + 2 / 2)]
16 - 4 [ 3 + 1 ]
16 - 4 [4]
16 - 16
0 <===
5 0
3 years ago
Read 2 more answers
The perimeter of a rectangular red sticker is 34 mm. it is 8 mm tall. how wide is it?​
Orlov [11]

Answer:

9 mm wide

Step-by-step explanation:

Perimeter = length x 2 + width x 2

34 mm = 16 mm + ?

34mm = 16 mm + 18 mm

18/2 = 9

9 mm wide

8 0
3 years ago
Read 2 more answers
What is the following product
Genrish500 [490]

For this case we must find the product of the following expression:

\sqrt [3] {5} * \sqrt {2}

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We rewrite the expression using the lowest common index of 6, then:

5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =

We rewrite the terms in an equivalent way:

5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =

We rewrite the expression using the property mentioned:

\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =

We combine using the product rule for radicals:

\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}

So:

\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}

ANswer:

Option b

4 0
3 years ago
A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. The number of subjects needed to estima
Ludmilka [50]

Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

8 0
3 years ago
Sketch a graph of the polynomial function f(x) =x3− 2x2. Use it to complete the following:
AlladinOne [14]

Answer:

We have the function:

f(x) = x^3 - 2*x^2

To sketch this, we need to graph some points, and then just draw a line that passes through the points.

The graph of this equation is shown below.

Now we can complete the question.

If the graph is below the x-axis in some interval, the function is negative in that interval

If the graph is above the x-axis in some interval, the function is positive in that interval.

If the graph goes up in a interval, then the function is increasing in that interval

If the graph goes down on an interval, then the function is decreasing in that interval.

Then:

1) f is------ on the intervals (−∞, 0) and (0, 2).

Here we can see that the graph is below the x-axis in those intervals, then here we have:

f is negative on the intervals (−∞, 0) and (0, 2).

2) f is------ on the interval (2,∞)

Here the answer is positive:

f is positive on the interval  (2,∞)

3) fi is ------ on the interval (0, 4/3)

In the graph, you can see that the graph goes down in that interval, then the correct answer here is:

f is decreasing on the interval (0, 4/3)

4) f is------ on the intervals (−∞, 0) and (4/3, ∞).

In this case, we can see that the graph goes up in these intervals, then the correct answer here is:

f is increasing on the intervals (−∞, 0) and (4/3, ∞).

5 0
3 years ago
Other questions:
  • Express each rate as a unit rate
    13·1 answer
  • Can anyone help me solve this in diffrent steps? 7(2.5m+m)=49
    12·1 answer
  • How do you work out 8 something 2 something 1 =24 ?
    9·2 answers
  • What is a rule for the sequence 1.8, 2.85, 3.90, 4.95, 6
    5·1 answer
  • The double number line shows that 111 pound of chocolate costs \$4$4dollar sign, 4.
    11·2 answers
  • Solve the equation 5w-5+4w-4
    15·1 answer
  • 100 and brainliest if you tell me ur favorite anime :]
    10·2 answers
  • PLEASE HELP ME ! Solve for x.
    11·2 answers
  • It took the football team 5 h to travel from Titletown, a total distance of 1320 km. Part of the trip was by bus and the remaind
    5·1 answer
  • HELP PLS will give brainliest-<br><br> please provide how to do it aswell
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!