Answer:
That's true. What are you asking?
Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.
<h3>What is the principal quantum number (n)?</h3>
The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.
n = 2 is the first excited state whose energy is calculated as:
Eₙ = − 13.6 ÷ n² eV
E₂ = - 13.6 eV ÷ 2²
= -3.40 eV
Therefore, -3.40 eV is the energy of electron at n = 2.
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Yes, Pb2+ react with KI.
Pb2+ is lead (II) ion
KI is a compound. It is a combination of potassium (K) and iodine (I). It is called potassium iodide.
Both potassium and iodine are highly reactive elements. Thus, when they are combined with another element like Pb2+, Pb2+ reacts with KI
Given what we know, the most appropriate way to find the concentration of orange candies is to take the exact number of orange candies and divide it by the total number of candies present.
<h3>Why is this the best method?</h3>
- This is the best method because it allows us to obtain a decimal value.
- This value will represent the percentage of candies in the total that are orange.
- In order to pass this decimal into a percent value, all we have to do is multiply by 100.
Therefore, we can conclude that by taking the total amount of orange candies and dividing by the total number of candies, we can obtain a decimal to illustrate the percent of total candies that are orange.
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