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Bond [772]
3 years ago
12

In tin at room temperature, the mobility of mobile electrons is about 1.5 ✕ 10⁻³ (m/s)/(V/m), and there are about 3.7 ✕ 10²⁸ mob

ile electrons per m³. Calculate the conductivity σ. In actual practice, it is usually easier to measure the conductivity σ and deduce the mobility u from this measurement.
Physics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

\sigma = 8.88 \times 10^6 \frac{1}{ohm-m}

Explanation:

As we know that mobility of electrons is given as

\mu = \frac{v_d}{E}

now we also know that

j = \sigma E

here we know

j = ne v_d

ne v_d = \sigma E

so we have

\sigma = ne \frac{v_d}{E}

\sigma = (3.7 \times 10^{28})(1.6 \times 10^{-19})(1.5 \times 10^{-3})

\sigma = 8.88 \times 10^6 \frac{1}{ohm-m}

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0.000025s

Explanation:

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A boy throws a ball into the air at 10.2 m/s. Assuming that only gravity acts on the ball, how high does it rise, in m?
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mgh = .5mv^2
Masses cancel out
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A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet
Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

K.E = 1/2 × m × v2

Where m is mass

v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

g is acceleration of free fall due to gravity = 9.8m/S2

h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

From the foregoing analysis of energy conversation it implies;

1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

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=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

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