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hoa [83]
3 years ago
15

A uniform diameter rod is weighted at end and is floating in a liquid. Determine if the liquid is (a) lighter than water, (b) wa

ter, or (c) heavier than water. Justify your answer.
Physics
1 answer:
Yakvenalex [24]3 years ago
4 0

(C) Heavier than water

<u>Explanation:</u>

Given

Diameter of the rod is uniform

The road is floating in a liquid.

Let the area of cross-section of the rod = A

Let the weight density of water = γw

Let the weight density of liquid = γl

Let the density of water = ρw

g is the gravitational force

So, weight of rod = density of the rod X volume

Wrod = ρw X g X ( A X 2L) + 2 ρwg (A X L)

Wrod = 4ρwgAL

Wrod = 4γwAL

We can see that the weight of the rod is more than the density of water. So, in water, the rod will sink.

If the rod is floating on the liquid then the liquid is heavier than the water.

Therefore, The liquid is heavier than the water.

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How to light prodeced by nature
frutty [35]
Natural sources of light include our sun and other stars, where the source of energy is nuclear energy (recall that the moon does not produce light but merely reflects sunlight), lightning, where the source is electrical, and fire, where the energy source is chemical.
4 0
3 years ago
A capacitor is to be constructed to have a capacitance of 100uF.The area of the plates is 6.om by 0.030m and the relative permit
lara [203]

Answer:

The answer is below

Explanation:

Given that:

The area of the plates is 6 m by 0.030 m, Therefore the area = 6 m × 0.03 m =  0.18 m²

the relative permittivity of dielectric (εr) is 7.0

Permittivity of free space (εo) = 8.854 × 10^(-12)

capacitance of 100uF

potential difference (V) of 12V

d = separation between plate

The capacitance (C) of a capacitor is given by:

C=\frac{\epsilon_o \epsilon_r A }{d}\\ 100*10^{-6}=\frac{8.854*10^{-12}*7*0.18}{d}\\ d=\frac{8.854*10^{-12}*7*0.18}{100*10^{-6}}=1.11*10^{-7}\ m

The electric field between plates is given as:

E = V /d

E = 12 / 1.11*10^{-7}=10.75*10^7\ V/m

3 0
4 years ago
A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part
Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

(I_p)s = \frac{\pi(0.55)4}2

      = 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

T_{max} = T_{allow} \frac{I_p}{r}

         =(14 \times 10^3) \times (\frac{0.14374}{0.55})

         = 3658.836 lb.in

         = \frac{3658.836}{12} lb.ft

        = 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

T_{max} = T_{allow}( \frac{Ip}{r})

          = (14 \times10^3) \times ( \frac{0.13101}{0.55})

          = 3334.8 lb.in

          = (\frac{3334.8}{12} ) lb.ft

          = 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

P_{max} = 2 \pi f_T

          = 2\pi(2.1) \times 304.9

          = 4023.061 lb. ft/s

          = (\frac{4023.061}{550}) hp

          = 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

P _{max,t} = 2\pi f_T

            = 2\pi(2.1) \times 277.9

            = 3666.804 lb.ft /s

            = (\frac{3666.804}{550})hp

            = 6.667 hp

7 0
3 years ago
Which sphere of Earth do humans exist in?
PolarNik [594]
Biosphere is the answer, hope i helped :))
4 0
3 years ago
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What is the calculation for elastic potential?
grin007 [14]
Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.
3 0
3 years ago
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