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pshichka [43]
3 years ago
15

A marathon runner completes a 42.188–km course in 2 h, 36 min, and 12 s. there is an uncertainty of 23 m in the distance travele

d and an uncertainty of 3 s in the elapsed time. calculate the percent uncertainty in the distance.
Physics
1 answer:
timurjin [86]3 years ago
4 0

The percentage uncertainty in the distance is <u>0.054%</u>.

Uncertainty in a measurement measures the deviation of the measured values from the true value.

The distance d can be expressed in the form <em>d+/-Δd, </em>where <em>Δd i</em>s the absolute uncertainty in the measurement of distance.

The percentage uncertainty  is given by,

Percentage uncertainty=\frac{\Delta d}{d} *100

The uncertainty in the measurement of distance is 23 m. Express the uncertainty in km.

\Delta d =\frac{23 m}{1000 m/km} =0.023 km

Calculate the percentage uncertainty in the distance.

\frac{\Delta d}{d} *100 =\frac{0.023 km}{42.188 km} *100=0.054 %

Thus, the percentage uncertainty in the measurement of distance is <u>0.054%</u>

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Orlov [11]

The number converted is 0.0467 \frac{(kg)(s)}{m^3}

Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

1 kg = 1000 g = 10^6 mg

1 min = 60 s

1 m^3 = 1000 L

The original unit that we have is

\frac{mg\cdot min}{L}

Therefore, it can be rewritten as:

=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot  60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}

Therefore, since the initial number was 0.779, the final value is

0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}

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Segmented mirrors sag under their own weight. their optical shape must be controlled by computer-driven thrusters under the mirr
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3 years ago
An 800 N man climbs 5 m up a ladder. How much gravitational potential energy does he gain?
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Answer:

4000J

Explanation:

Given parameters:

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Now insert the parameters;

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a waves amplitude is 0.5 meters. If the amplitude is increased to 1 metro, how does its energy change
marysya [2.9K]

Answer:

The energy becomes 4 times greater.

Explanation:

We know that the energy of a wave is proportional to the square of its amplitude

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Since the original amplitude = 0.5 m

and the new amplitude becomes = 1 m

We are doubling the amplitude. This means that the new energy will be affected by a factor of 4

E_new  ∝ (2*Amplitude)^2  =

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Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector
Sav [38]
Good morning.

We see that \mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}

The magnitude(norm, to be precise) can be calculated the following way:

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