Answer:
The vapor pressure of the solution is 3.69 torr
Explanation:
Step 1: Data given
Mole fraction of benzene in the solution = 0.139
P° of benzene is 26.5 torr
Step 2: Calculate the vapor pressure of the solution
Psolution = Xbenzene * P°benzene
⇒with Psolution = the vapor pressure of the solution
⇒with Xbenzene = the mole fraction of benzene = 0.139
⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr
Psolution = 0.139 * 26.5 torr
Psolution = 3.69 torr
The vapor pressure of the solution is 3.69 torr
Answer:
es esto OH−
Explanation:
el hidróxido es hidrógeno unido covalentemente al oxígeno. Es un anión y tiene carga negativa.
Answer:
About bonding
Explanation:
A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bond.
Answer:
transfer
Explanation:
as heat flows from one object to another, the first object loses the heat(energy), while the second object gains heat(energy).
If you have any questions don't hesitate to ask :)
Answer:
See explanation
Explanation:
In order to do this, we need to use 3 reagents to get the final product.
The first one, and logic is the halogenation of the alkene. Doing this, with Br2/CCl4, we'll get an alkane with two bromines, one in carbon 2 and the other in carbon 3.
Then, the next step is to eliminate one bromine of the reactant. The best way to do this, is using sodium ethoxide in ethanol. This is because sodium ethoxide is a relatively strong base, and it will promove the product of elimination in major proportions rather than the sustitution product. If we use NaOH is a really strong base, and it will form another product.
When the sodium ethoxide react, it will form a double bond between carbon 1 and 2 (The carbon where one bromine was with the methyl, changes priority and it's now carbon 3).
The final step, is now use acid medium, such H3O+/H2O or H2SO4/H2O. You can use any of them. This will form an carbocation in carbon 2 (it's a secondary carbocation, so it's more stable that in carbon 1), and then, the water molecule will add to this carbon to form the alcohol.
See the attached picture for the mechanism of this.