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klio [65]
3 years ago
6

A population of Esherichia coli is given time to grow for eight generations. The final population is 1,996,800 cells. What was t

he initial population in cells?
Chemistry
1 answer:
hram777 [196]3 years ago
7 0

Answer:

7800 cells

Explanation:

The number of Escherichia coli cells N after n generations is given by

N = 2ⁿ × N₀ where N₀ = initial population

Now making N₀ subject of the formula, we have

N₀ = N/2ⁿ

Since n = 8 and N = 1,996,800 cells, substituting the values of the variables into the equation, we have

N₀ = N/2ⁿ

N₀ = 1,996,800 cells/2⁸

N₀ = 1,996,800 cells/256

N₀ = 7800 cells

So, the initial population of Escherichia coli cells is 7800 cells.

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<h3>A. Balanced equation </h3>

The balanced equation for the reaction between acetylene gas (C₂H₂) and oxygen gas (O₂) is given below

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Since the reaction occurred at standard temperature and pressure, we can thus say that:

From the balanced equation above,

2 L of C₂H₂ reacted with 5 L O₂.

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<h3>C. How to determine the volume of carbon dioxide </h3>

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

From the balanced equation above,

2 L of C₂H₂ reacted to produce 4 L of CO₂

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<h3>D. How to determine the volume of water. </h3>

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From the balanced equation above,

2 L of C₂H₂ reacted to produce 2 L of H₂O

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0.7 L of C₂H₂ will also react to produce 0.7 L of H₂O

Thus, 0.7 L of H₂O was produced

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brainly.com/question/14735801

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