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2 years ago

Use the following information to answer Q1-Q3

Chemistry

1 answer:

Tju [1.3M]2 years ago

4 0

Answer:

Likely the reason behind carrying them in liquid for is to condense them. liquid takes up far less space than gases do and will last far longer. they can be transformed back into gases through heating them back up. To keep them solid would require frigid temperatures but liquid will transfer more easily through space.

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A sample of aspirin weighing 5.945 g became contaminated with 2.134 g of sodium sulfate. The resulting

ira [324]

Answer:

The correct answer to the following question will be "62.9 %".

Explanation:

The given values are:

The aspirin's initial amount = 5.945 g.

and is polluted containing 2,134 g of sodium sulfate.

After extraction we provided 3,739 g of pure aspirin.

Now,

$Percentage \ of \ recovery \ aspirin =\frac{Aspirin \ amount \ isolated \ after \ extraction}{initial \ amount \ of \ aspirin}\times 100$

On putting the values in the above formula, we get

⇒ $=\frac{3.739}{5.945}\times 100$

⇒ $=62.9 \ percent$

Note: percent = %

7 0

3 years ago

, glucose is converted into what three products? science

Ivenika [448]

Answer:

carbon dioxide, water, sunlight

6 0

3 years ago

Read 2 more answers

With what compound will nh3 experience only dispersion intermolecular forces? with what compound will nh3 experience only disper

Burka [1]

Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

6 0

3 years ago

Read 2 more answers

What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

8 0

3 years ago

A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.

Rufina [12.5K]

From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1
mm1 = 71/1.87²
= 71/3.4969
= 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon

6 0

3 years ago