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gregori [183]
3 years ago
7

If the mass of an object is 2 g and the volume is

Chemistry
1 answer:
PolarNik [594]3 years ago
7 0

Answer:

<h2>The answer is option A</h2>

Explanation:

To find out if the object sink or float in water we must first find the density of the object

density =  \frac{mass}{volume}  \\

From the question

mass of object = 2 g

volume = 4 mL

The density is

density =  \frac{2}{4}  =   \frac{1}{2}

We have the answer as

0.5 g/mL

The object will float on water since it's density is less than that of water which is

1.0 g/mL

Hope this helps you

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Which mineral would most likely be found in a necklace? graphite, halite, sulfur, or emerald?​
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What is the missing part of the chemical equation shown below? acid + base ? salt + ________
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Water is the answer.
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Consider the reaction when aqueous solutions of potassium hydroxide and ammonium nitrate are combined. The net ionic equation fo
Reil [10]

Answer: OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

KOH(aq)+NH_4NO_3(aq)\rightarrow KNO_3(aq)+NH_3(g)+H_2O(l)

The equation can be written in terms of ions as:

K^+(aq)+OH^-(aq)+NH_4^+(aq)+NO_3^-(aq)\rightarrow K^+(aq)+NO_3^-(aq)+NH_3(g)+H_2O(l)

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

6 0
3 years ago
Based on the equation 3 Cu (s) + 8 HNO3 (aq) 3 Cu(NO3)2 (aq) + 2NO (g) + 4H2O (g) how many grams of Cu would be needed to react
eimsori [14]

Answer:

Mass = 381.28 g

Explanation:

Given data:

Number of moles of HNO₃ = 16 mol

Mass of Cu needed to react with 16 mol of HNO₃ = ?

Solution:

Chemical equation:

3Cu + 8HNO₃    →     3Cu(NO₃)₂ + 4H₂O + 2NO

Now we will compare the moles of Cu with HNO₃ from balance chemical equation.

                     HNO₃         :          Cu

                        8              :         3

                       16             :       3/8×16 = 6

Mass of Cu needed:

Mass = number of moles × molar mass

Mass = 6 mol × 63.546 g/mol

Mass = 381.28 g

4 0
3 years ago
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