2n² rule:
This rule is used to determine number of electrons in particular shell.
n=1 means K shell
n=2 means L shell
n=3 means M shell
n=4means N shell
The first K shell can hold upto 2 electrons, L shell can hold up to 8, third M shell can hold up to 18and the fourth N shell can hold upto 32 electrons. This rule of arrangement of electrons according to the shell is known 2n2 rule where n means number of shell.
For example: There is one proton in the nucleus of hydrogen atom, which moves in K shell path. It has no neutron.
Answer:
Explanation:
48.16%
Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.
Hope This Helps :)
D) energy required to remove a valence electron
Explanation:
The ionization energy is the energy required to remove a valence electron from an element.
Different kinds of atoms bind their valence electrons with different amount of energy.
- To remove the electrons, energy must be supplied to the atom.
- The amount of energy required to remove the an electron in the valence shell is the ionization energy or ionization potential.
- The first ionization energy is the energy needed to remove the most loosely bound electron in an atom in the ground state.
- The ionization energy measures the readiness of an atom to loose electrons.
Learn more:
Ionization energy brainly.com/question/5880605
#learnwithBrainly
<u>Answer:</u> The concentration of solution is 0.342 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (Sodium chloride) = 15 g
Molar mass of sodium chloride = 58.5 g/mol
Volume of solution = 750 mL
Putting values in above equation, we get:

Hence, the concentration of solution is 0.342 M