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Yakvenalex [24]
3 years ago
5

Help im struggling frfr

Chemistry
2 answers:
ki77a [65]3 years ago
5 0

Answer:

it is dilute

Explanation:

babunello [35]3 years ago
4 0

Answer:

answer is  c

Explanation:

I think we have the same class

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What is the percent by mass of potassium in KFe(CN)?
vladimir1956 [14]

Answer:

Explanation:

1. Add the atomic mass of all the elements.

39+55.8+12+14= 120.8

2.Divide atomic mass of potassium by total atomic mass

39/120.8= .323

2. Multiply by 100

.323*100= %32.3 %32.3

8 0
4 years ago
On many common appliances, there is an “O” or “I” on the power switch. What does each symbol mean?
Art [367]

"I" symbol means the current goes through the system (imagine the 'I' being a line, like a circuit connecting [power to the device]) "O" symbol means the current does not go through the system. ( the circle is an open circuit, having no power flowing through it
3 0
3 years ago
In a science experiment, Javi concludes that a chemical reaction has occurred. What evidence would support this conclusion?
Naily [24]

Answer:

B) a substance's color and odor changed        Explanation: A signal that a chemical change has occurred is when its odor (its smell) or its appearance has changed.

8 0
3 years ago
Read 2 more answers
A gas occupies 3.5L at 2.5 kPa pressure. What is the volume at 100 mmHg at the same temperature? Be sure to
nataly862011 [7]

Answer:

V₂ = 0.656 L

Explanation:

Given data:

Initial volume = 3.5 L

Initial pressure = 2.5 KPa

Final volume = ?

Final pressure = 100 mmHg (100/7.501=13.33 KPa)

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

2.5 KPa × 3.5 L = 13.33 KPa × V₂

V₂ = 8.75 KPa. L/13.33 KPa

V₂ = 0.656 L

7 0
3 years ago
A sample of sulfur hexafluoride gas occupies a volume of 9.10 L at 198ÁC. Assuming that the pressure remains constant, what temp
alexandr1967 [171]
  As we know that
<span>V1/T1 = V2/T2 
V1 = 9.10 L 
T1 = 471 K 
V2 = 2.50 L 
T2 = 2.5 x 471 / 9.10 = 129.3 K 
T2 = 129.3 - 273 =
 -143.6 deg Celsiu
hope it helps</span>
5 0
3 years ago
Read 2 more answers
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