The density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³
<h3>What is Density ?</h3>
Density is the measurement of how tightly a material is packed together.
It is defined as the mass per unit volume.
Given ;
- Mass = 23.5 g
- Volume = 13.5 cm³
Formula to calculate density ;
Density = mass / volume
=23.5 / 13.5 = 1.74 g/cm³
Hence, the density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³.
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Answer:
60.02 g.
Explanation:
- It is clear from the balanced equation:
<em>Mg + 2HCl → MgCl₂ + H₂.
</em>
that 1.0 mole of Mg reacts with 2.0 moles of HCl to produce 1.0 mole of MgCl₂ and 1.0 moles of H₂.
- 20.0 g of Mg reacts with excess HCl. To calculate the no. of grams of HCl that reacted, we should calculate the no. of moles of Mg:
<em>no. of moles of Mg = mass/atomic mass</em> = (20.0 g)/(24.3 g/mol) = 0.823 mol.
- From the balanced equation; every 1.0 mol of Mg reacts with 2 moles of HCl.
∴ 0.833 mol of Mg will react with (2 x 0.833 mol = 1.646 mol) of HCl.
<em>∴ The mass of reacted HCl = no. of moles x molar mass</em> = (1.646 mol)(36.46 g/mol) = <em>60.02 g.</em>
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