Answer:
V = 240 
Step-by-step explanation:
To find the volume of a rectangular prism use this equation:
V = l*w*h
l = length (20 cm)
w = width (4 cm)
h = height (3 cm)
Plug all these values into the equation and solve:
V = (20 cm)(4 cm)(3 cm)
V = (80
)(3 cm)
V = 240 
Therefore, the volume of the rectangular prism is 240
.
I hope this helps! Good luck!
Answer:
32.9 inches
Step-by-step explanation:
this can be solved using Pythagoras theorem
The Pythagoras theorem : a² + b² = c²
where a = length
b = base = 49
c = hypotenuse = diagonal = 59
l² + 49² = 59²
l² = 59² - 49²
3481 - 2401 = 1080
find the square root
32.9 in
The formula is as follows
V = L*W* H
V = 12.1 cm * 5.3 cm * 4.2 cm
V =269.346 cm^3
rounded to the nearest tenth
V = 269.3 cm^3
Choice D
9 would be ur answer....because 9 is an odd number greater then 2, but it is not a prime number
Answer:
The solution of the Given matrix
( x₁ , x ₂ ) = ( - 5 , 4 )
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equations are x₁+4 x₂ = 11 ...(i)
2 x₁ + 7 x₂= 18 ...(ii)
The matrix form
A X = B
![\left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C2%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<u>Step(ii):-</u>
![\left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C2%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The Augmented Matrix form is
![[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]](https://tex.z-dn.net/?f=%5BAB%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%2611%5C%5C2%267%2618%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Apply Row operations, R₂ → R₂-2 R₁
The matrix form
![\left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%5C%5C-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The equations are
x₁ + 4 x₂ = 11 ...(a)
- x ₂ = - 4
x ₂ = 4
Substitute x ₂ = 4 in equation (a)
x₁ + 4 x₂ = 11
x₁ = 11 - 16
x₁ = -5
<u>Final answer</u>:-
The solution of the Given matrix
( x₁ , x ₂ ) = ( - 5 , 4 )