2. What happens to the temperature of air when it is compressed?

Chemistry

2 answers:

professor190 [17]3 years ago

4 0

Explanation:

the pressure and temperature of the air increase

reason:

the volume of the space containing air decreases.

Alex_Xolod [135]3 years ago

3 0

Explanation:

Whether you know it or not, compressed air is involved in every aspect of our lives, from the balloons at your birthday party to the air in the tires of our cars and bicycles. It was probably even used when making the phone, tablet or computer you’re viewing this on.

The main ingredient of compressed air is - you guessed it! - air. Air is a gas mixture, which means it consists of many different gases. Primarily these are nitrogen (78%) and oxygen (21%).

The temperature of the air is directly proportional to the mean kinetic energy of these molecules. This means that the air temperature will be high if the mean kinetic energy is large (and the air molecules move faster). The temperature will be low when the kinetic energy is small.

Compressing the air makes the molecules move more rapidly, which increases the temperature. This phenomenon is called “heat of compression”. Compressing air is literally to force it into a smaller space and as a result bringing the molecules closer to each other. The energy that gets released when doing this is equal to the energy required to force the air into the smaller space. In other words, it stores the energy for future use.

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zalisa [80]

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3 years ago

30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140

kolbaska11 [484]

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT = $\frac{Q}{mc}$