Answer:
Entropy is a measurement of how much the atoms in a substance are free to spread out, move around, and arrange themselves in random ways
Hi there!
The statement that correctly describes how telescopes have changed over time is 'B'
When gas is dissolved in a liquid, more gas dissolves into the liquid. It states that when the pressure of the gas when dissolved in liquid increases, the solubility increases. Thus, the correct option is C.
<h3>What is Pressure?</h3>
Pressure may be defined as the amount of force devoted perpendicular to the surface of an object per unit area. The unit of pressure is Pascal or Pa.
The solubility of any solution is directly proportional to the pressure that is exerted on it at a given time. As the pressure increases, more the solute dissolves into the solvent.
Therefore, the correct option for this question is C.
To learn more about Solubility, refer to the link:
brainly.com/question/23946616
#SPJ1
Answer:
The number following the name of the element is the number of subatomic particles inside the nucleus of the atom. This means that it is the mass number of the isotope. The average atomic mass of the element is the sum of the products of the percentage abundance and mass number of the naturally occurring isotopes.
Since, the average atomic mass of the hydrogen is nearest to 1 then, the most abundant isotope should be hydrogen-1.
Answer:
Nitrogen molecule (N2)
The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.
N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2
Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.
The bond order of N2can be calculated as follows:
Here, Nb = 10 and Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
So your answer should be C3.
