Answer:
The speed of light in glycerol is 2.04×108 m/s .
Explanation:
The magnitude of the change in potential energy is equal to the kinetic energy,

or
Here, V is potential difference, q is charge, m is mass and v is velocity.
We can also write,

Given 
Substituting this value with mass of proton,
and charge of proton,
we get

Therefore, the speed of proton is
.
Answer:
3.1 m/s
Explanation:
The acceleration of the ball is given by:

where
v is the final velocity
u is the initial velocity
t is the time elapsed
Here we know:
a = 1.8 m/s^2 is the acceleration
v = 7.6 m/s is the final velocity
t = 2.5 is the time elapsed
Solving for u, we find the initial velocity of the ball:
