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3 years ago

Ten examples of non luminous objects

Physics

2 answers:

Tems11 [23]3 years ago

8 0

Answer:

1) moon

2) house

3) trees

4) stones

5) metals

6) furniture

7) comments

8) soil

9) wall

Kipish [7]3 years ago

6 0

Answer:

1.moon

2.person

3.Table

4.chair

5.Windows

6.Books

7.pens

8.Brick

Explanation:

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Find the buoyant force on a brass block 10.5 cm long by 12.3 cm wide by 15.0 cm high when placed in (a) water, (b) glycerine, an

STALIN [3.7K]

Answer:

(a) F = 18.99 N

(b) F = 23.96 N

Explanation:

First we need to find the volume of the block:

Volume of Block = V = (Length)(Width)(Height)

V = (10.5 cm)(12.3 cm)(15 cm)

V = (0.105 m)(0.123 m)(0.15 m)

V = 0.00194 m³

Now, the buoyant force i given by the formula:

F = (Density of Fluid)(V)(g)

(a)

F = (Density of Water)(V)(g)

F = (1000 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 18.99 N

(b)

F = (Density of Glycerine)(V)(g)

F = (1260 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 23.96 N

(c)

F = (Density of Mercury)(V)(g)

F = (13600 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 258.56 N

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3 years ago

If you pushed of the wall just standing, why would you move less just standing then if you were on a scooter?

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Answer:

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3 years ago

Distance Using Hubble's Law II.Find the percent difference (% = |A-O|/A × 100) between the actual (A) distance values and calcul

wlad13 [49]

Answer:

Explanation:

Let us first calculate for Virgo

$A= d_{virgo} = 17;M_{pc}, V_{virgo} = 1200 km/s,
$

Using Hubble's law

$v = H_{0}D$ For Virgo

$V_{virgo} = H_{0}D_{virgo}$

$O = D_{virgo} = \frac{v_{virgo}}{H_{0}} = \frac{1200 km/s}{70 km/s/Mpc}= 17.143 Mpc
$

Percentage difference for the Virgo

$\% = \frac{|A-O|}{A}\times 100 = \frac{|17 Mpc-17.143 Mpc|}{17 Mpc}\times 100 = 0.84 \%
$

Now for calculate for Corona Borealis

$A= d_{Corona Borealis} = 310 Mpc, v_{Corona Borealis} = 22000 km/s,
$

Using Hubble's law

$v = H_{0}D$ For Corona Borealis

$v_{Corona Borealis } = H_{0}D_{Corona Borealis }
\\O = D_{Corona Borealis } = \frac{v_{Corona Borealis }}{H_{0}} = \frac{22000 km/s}{70 km/s/Mpc}= 314.286 Mpc
$

Percentage difference for the Virgo

$\% = \frac{|A-O|}{A}\times 100 = \frac{|310 Mpc-314.286 Mpc|}{310 Mpc}\times 100 = 1.3825 \%
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So clearly Hubble's law is more accurate for the closer objects

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4 years ago

Calculate the momentum of a 1950 kg elephant charging a hunter at a speed of 7.50 m/s. (b) Compare the elephant's momentum with

prisoha [69]

Answer:

a) (momentum of the elephant), p1 = 14625 kg×m/s

b) p1 = 609.4×p2

c) (momentum of the hunter), p3 = 720 kg×m/s.

Explanation:

a) if m = 1950 kg is the mass of the elephant and V = 7.50 m/s be the speed of the elephant, then the momentum is given by:

p1 = m×V = (1950)×(7.50) = 14625 kg×m/s

b) if m = 0.0400 kg is the mass of the bullet and v = 600 m/s be the speed of the bullet, then the momentum of the bullet is given by:

p2 = m×v = (0.0400)×(600) = 24 kg.m/s

then:

p1/p2 = (14625)/(24) = 609.4

that is, p1 = 609.4×p2

Therefore, the momentum of the elephant is 609.4 times the momentum of the bullet.

c) the momentum og the hunter after missing the elephant is given by:

p3 = m×v = (90.0)×(8) = 720 kg.m/s

Therefore, the momentum of the hunter is 720 kg×m/s.

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4 years ago

A fruit bat falls from the roof of a cave. We know that her potential energy was

bulgar [2K]

Answer:

v = 15.65 m/s

Explanation:

We use conservation of mechanical energy between initial (i) and final (f) states:

Pi + KEi = Pf + KEf

At the top of the cave at the instant the bat starts to fall, there is only potential energy since the bat's velocity is zero.

Pi = m g h = 600 J

and the KEi = 0 J (no velocity)

Knowing the height of the cave's roof (12.8 m) , we can find the mass of the bat:

m = 600 J / (g 12.5) = 4.9 kg

Using conservation of mechanical energy, the final state is:

Pf + KEf = 600 J

with Pf = 0 (just touching the ground)

KEf= 1/2 4.9 (v^2)

and we solve for the velocity:

600 J = 0 + 1/2 4.9 (v^2)

v^2 = 600 * 2 / 4.9 = 244.9

v = 15.65 m/s

5 0

3 years ago

Ten examples of non luminous objects​

Ten examples of non luminous objects