If Earth's axis was "straight up and down" instead of tilted, then ...
<span>-- There would be no seasons.
-- The climate at any one place would be the same all year around.
-- The days would be the same length, everywhere,
and all year around.
-- So would the nights.
-- The sun would be up a little more than 12 hours every day.
It would be down a little less than 12 hours every day.
-- At the middle of the day, the sun would be at the same height
in the sky all year around, not higher in some months and lower
in others.
-- The equator would be the only place on Earth where the sun
could ever be directly over your head.
-- If you were at the north pole or the south pole, the sun would be
down on the horizon, and it would just go around and around you
every day. It would never rise or set, and it would never get any
higher or lower.
</span>
The magnitude of the net displacement is 95.3 m
Explanation:
To find the magnitude of the net displacement, we have to resolve each of the two displacements into the horizontal and vertical direction first.
1st displacement is:
at 
So its components are

2nd displacement is:
at 
So its components are

Therefore, the x- and y-components of the net displacement are:

Therefore, the magnitude of the final displacement is:

Learn more about displacement:
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Answer:
388.97 nm
Explanation:
The computation of the wavelength of this light in benzene is shown below:
As we know that
n (water) = 1.333
n (benzene) = 1.501

And, the wavelength of water is 438 nm
![\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]](https://tex.z-dn.net/?f=%5Clambda%20%28benzene%29%20%3D%20%5Clambda%20%28water%29%20%5B%5Cfrac%7Bn%28water%29%7D%7Bn%28benzene%7D%5D)
Now placing these values to the above formula
So,

= 388.97 nm
We simply applied the above formula so that we can easily determine the wavelength of this light in benzene could come
Answer:
a) load in Newton is 96,138 b) 129.314mm
Explanation:
Stress = force/ area (cross sectional area of the bronze)
Force(load) = 294*10^6*327*10^-6 = 96138N
b) modulus e = stress/ strain
Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3
Strain = change in length/ original length = DL/ 129
Change in length DL = 129 * 2.34*10^ -3 = 0.31347
Maximum length = change in length + original length = 129.314mm