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2 years ago

7

turning on the television is a form of _ energy that transforms into _ energy and/or sound energy

1 answer:

MariettaO [177]2 years ago

8 0

Electric energy into light energy and sound energy

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if the time is taken to bring a ball to rest from a certain velocity 'v'. is reduced to half, what will be the change in the val

777dan777 [17]

The answer is C) rate of change of momentum. The answer is not initial or final momentum as the start and end points are not changing. On the other hand, the time it takes for the ball to change velocity is. This change relates to the change of momentum. Hope this helped :))

6 0

2 years ago

(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th

Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:

$V_{f}^{2} = V_{0}^{2} - 2gh$

<u>Where:</u>

$V_{f}$ : is the final speed = 14 m/s

$V_{0}$ : is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

$V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s$

b) The maximum height is:

$V_{f}^{2} = V_{0}^{2} - 2gh$

$h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m$

c) The time can be found using the following equation:

$V_{f} = V_{0} - gt$

$t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s$

d) The flight time is given by:

$t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s$

I hope it helps you!

3 0

3 years ago

The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and

Kruka [31]

The strength of the electric field will be 215760 NC⁻¹. The concept of the electric field strength is used in the problem.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge. Its unit is NC⁻¹.

The given data in the problem is;

E is the Electric Field Strength

k is the Colomb's constant = 8.99 x 10⁹ N.m²/C²

q is the magnitude of charge = 6 μC = 6 x 10⁻⁶ C

r is the distance = 0.5 m

The electric field strength is given by the formula;

$\rm E = \frac{Kq}{R^2} \\\\ \rm E = \frac{8 .99 \times 10^9 6 \times 10^6 }{(0.5)^2} \\\\ E=215760 \ NC^{-1}$

Hence the strength of the electric field will be 215760 NC⁻¹.

To learn more about the electric field strength refer to the link;

brainly.com/question/4264413

6 0

1 year ago

What is the difference between dense wavelength division multiplexing and coarse wavelength division multiplexing

Kipish [7]

The difference is the difference it is what it is I’m sorry

7 0

2 years ago

Matt is driving down 7th street. He drives 150 meters in 18 sec. assuming he doesn’t slow down or speed up, what is his speed?

Romashka [77]

8.3(repeating) m/ps

S=D/T

150/18=8.3333....

6 0

2 years ago