Answer:
a) 6076 m
b) 43.33 m/s
c) 68 m/s
Explanation:
(a) If the airplane rounds half the circle in 156s, its displacement is the circle diameter in 156s, or twice the circle's radius
s = 2r = 2* 3.38km = 6.76 km or 6760 m
(b) The average velocity would be displacement over unit of time
v = s/t = 6760 / 156 = 43.33 m/s
(c) The length of the chord it's swept in 156s is half of the circle perimeter
c = πr = π3.38 = 10.62 km or 10620 m
The airplane average speed is its chord length over a unit of time
c / t = c / 156 = 68 m/s
You have said that 15cm³ of gold weighs 2.8N. So I may infer that each cm³
of gold weighs about 0.19N. When I compare that figure with the 0.13N per cm³
of mercury, it becomes immediately apparent that the gold is more dense than
mercury. Therefore, the sample of gold, no matter what its size or weight, will
displace its total volume of mercury, and will go on to sink entirely beneath the
waves in the mercury.
Answer:
Explanation:
We use the following rotational kinematic equation to calculate the angular acceleration of the rod:
Here 
is the final angular speed, 
is the initial angular speed and 
is the angular acceleration. The rod starts rotating from rest (
):
Recall that the angular speed is defined in function of the tangential speed (v) and the radius (r) of the circular motion:
In this case the radius is given by 
. Replacing (2) in (1):
Answer:
gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)
