Ask question

Ask question

All categories

3 years ago

13

The perimeter of a triangle is 38cm. The first side is 10cm longer than the second side, the third side is twice as long as the

second side, what are the three side lengths?

1 answer:

Natalija [7]3 years ago

8 0

Side 1: 17 Cm.
Side 2: 7 Cm.
Side 3: 14 Cm.

Hope This Helped.

You might be interested in

Plz solve this if u know plz

salantis [7]

<h3>Solution:</h3>

${64}^{ - \frac{1}{3} } ( {64}^{ \frac{1}{3} } - {64}^{ \frac{2}{3} } ) \\ {64}^{ \frac{1}{3} - \frac{1}{3} } - {64}^{ \frac{2}{3} - \frac{1}{3} } \\ {64}^{0} - {64}^{ \frac{1}{3} } \\ 1 - \sqrt[3]{64} \\ 1 - 4 \\ - 3$

<h3>Answer:</h3>

$- 3$

5 0

3 years ago

Read 2 more answers

What does one half of a number is four look like

Kitty [74]

Answer:

$\frac{1}{4} x = 4$

Step-by-step explanation:

$\frac{1}{4} x = 4$

Let's solve:

$\frac{1}{4} x = 4$

4( $\frac{1}{4} x = 4$ )

x = 16

Let's check:

$\frac{1}{4} x = 4$

$\frac{1}{4}(16) = 4$

4 = 4

Hope this helps!

6 0

3 years ago

Read the picture above

Romashka-Z-Leto [24]

Vitvivuc vrivdfdxfdddxgtdcgyimbfdd

5 0

3 years ago

What is the area of the figure in the picture above?

jek_recluse [69]

The square area is 6*6=36
For the two triangles, the area is base*height/2 = 6*3 = 18.
So the total area is 18+36+18=72

4 0

4 years ago

Cos10+cos80/sin10+sin80=1

eduard

Evaluate <span><span>cos<span>(10)</span></span><span>cos10</span></span> to get <span>0.984807750.98480775</span>.<span><span><span>0.98480775<span>cos<span>(80)</span></span></span><span><span>−<span>sin<span>(10)</span></span></span><span>sin<span>(80)</span></span></span></span><span><span>0.98480775⁢<span>cos80</span></span><span><span>-⁢<span>sin10</span></span>⁢<span>sin80</span></span></span></span>Evaluate <span><span>cos<span>(80)</span></span><span>cos80</span></span> to get <span>0.173648170.17364817</span>.<span><span><span>0.98480775⋅0.17364817</span><span><span>−<span>sin<span>(10)</span></span></span><span>sin<span>(80)</span></span></span></span><span><span>0.98480775⋅0.17364817</span><span><span>-⁢<span>sin10</span></span>⁢<span>sin80</span></span></span></span>Multiply <span>0.984807750.98480775</span> by <span>0.173648170.17364817</span> to get <span>0.171010070.17101007</span>.<span><span>0.17101007<span><span>−<span>sin<span>(10)</span></span></span><span>sin<span>(80)</span></span></span></span><span>0.17101007<span><span>-⁢<span>sin10</span></span>⁢<span>sin80</span></span></span></span>Evaluate <span><span>sin<span>(10)</span></span><span>sin10</span></span> to get <span>0.173648170.17364817</span>.<span><span>0.17101007<span><span><span>−1</span>⋅0.17364817</span><span>sin<span>(80)</span></span></span></span><span>0.17101007<span><span><span>-1</span>⋅0.17364817</span>⁢<span>sin80</span></span></span></span>Multiply <span><span>−1</span><span>-1</span></span> by <span>0.173648170.17364817</span> to get <span><span>−0.17364817</span><span>-0.17364817</span></span>.<span><span>0.17101007<span><span>−0.17364817</span><span>sin<span>(80)</span></span></span></span><span>0.17101007<span><span>-0.17364817</span>⁢<span>sin80</span></span></span></span>Evaluate <span><span>sin<span>(80)</span></span><span>sin80</span></span> to get <span>0.984807750.98480775</span>.<span><span>0.17101007<span><span>−0.17364817</span>⋅0.98480775</span></span><span>0.17101007<span><span>-0.17364817</span>⋅0.98480775</span></span></span>Multiply <span><span>−0.17364817</span><span>-0.17364817</span></span> by <span>0.984807750.98480775</span> to get <span><span>−0.17101007</span><span>-0.17101007</span></span>.<span><span>0.17101007<span>−0.17101007</span></span><span>0.17101007<span>-0.17101007</span></span></span>Subtract <span>0.171010070.17101007</span> from <span>0.171010070.17101007</span> to get <span>0</span>.0

7 0

3 years ago