Answer:
θ = 3.38 degrees
r = 0.48mi
Explanation:
a) Start by converting 1.7 mi into feet.
1mile = 5280 feet,
so 1.7 mi = 8976 ft

so ![\theta = sin^{1] {530}{8976}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20sin%5E%7B1%5D%20%7B530%7D%7B8976%7D)
and θ = 3.38 degrees
b )Now to gain another 150 ft of elevation, again use the
equation y=rsin(θ)
150 = rsin(3.38)
r = 2544.187 ft.
Convert r = 2544.187 ft into miles by dividing by 5280,
and r = 0.48mi
Wave speed = (wavelength) x (frequency)
= (4 m) x (2 /sec)
= 8 m/sec
Yes I can do you want me to
Answer:
Explanation:
Gravitational potential energy = mass x height of object x g
g is gravitational acceleration .
Gravitational potential energy of the ball = .600 x 2.20 x 9.8
= 12.936 J .
12.9 J .
The elastic potential energy increases by a factor of 9
Explanation:
The elastic potential energy of a bowstring is given by
(1)
where
k is the spring constant
x is the elongation of the bowstring
Hooke's law states the relationship between the force applied and the elongation of an elastic object:

where
F is the force applied
x is the elongation
We can rewrite it as

And substituting into (1),

In this problem, the force applied to the bowstring is tripled,
F' = 3F
So the final elastic potential energy is:

So, the elastic potential energy increases by a factor of 9.
Learn more about potential energy:
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