Answer:
the higher the mass the faster it falls so you need to know the mass to know how fast or slow it will fall
If the resistance of each bulb is 3 ohms, and they are connected across the battery, then current will flow through them.
In series, the two 3-ohm bulbs will look like a single 6-ohm resistance.
Current = (voltage) / (resistance) = (12v) / (6 ohms) = 2 Amperes.
The battery will need to deliver some power to the circuit.
Power = (voltage) x (current) = (12v) x (2 Amperes) = 24 watts .
Each bulb will dissipate 12 watts, in the form of light and heat.
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Answer:
Here Are Some Tanning Bed Tips For Beginners To Help You Get The Most .Knowing your skin type before you tan can help you to do so safely and help . If you want to ensure you get a quality tan, you first need to be certain your . Obviously, if you wear a bathing suit, you'll get tan lines from the suit. Apply indoor tanning lotion evenly in a circular motion and over all areas of the body. Using the right skin care products is the best way to extend the life of your tan. Note that lotions not made for indoor tanning can cause damage to tanning beds and don't help develop your tan. So what (if anything) should you wear? There are a lot of different views on this particular question, and it all comes down to one very simple answer: wear whatever you are comfortable in. If you wear your bathing suit every time, you will have tan lines that reflect that, but that's your choice.
Explanation:
Density of powder 1 = 0.5 g / 45 cm^3 = 1/90 g/cm^3
Density of powder 2 = 1.3 g / 65 cm^3 = 1/50 g/cm^3
Therefore the densities of the two powders are different, hence chemical reaction has occurred.
(note: none of the other choices make sense. In fact, a different density does not necessarily indicate a chemical change, see paragraph below).
Density of powders are not definitive unless they are each of the same size and texture. For example, granular sugar, rock sugar, and icing sugar all have different densities. I would conclude that this experiment does not lend to a reliable answer.