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viktelen [127]
3 years ago
10

The cruise control of megan's truck is set at 65 miles per hour, but her actual speed may vary by as much as 5 miles per hour. W

rite an inequality that can be used to determine the actual speeds at which megan could be traveling.
Physics
2 answers:
LenKa [72]3 years ago
5 0
<span>-65|≤5 is the right answer
hope it helps
</span>
kobusy [5.1K]3 years ago
3 0

Answer:

The required inequality is |s - 65| ≤ 5.

Explanation:

Consider the provided information.

The cruise control of Megan's truck is set at 65 miles per hour, but her actual speed may vary by as much as 5 miles per hour.

That means actual speed can be 65 - 5 or 65 + 5

Let the speed of Megan's truck is "s".

The speed of truck is lies between 65 - 5 or 65 + 5

This can be written as:

65 - 5 ≤ s ≤ 65 + 5

60 ≤ s ≤ 70

Or this can be written as:

65 - 5 ≤ s ≤ 65 + 5

Subtract both the side by 65.

- 5 ≤ s - 65 ≤ 5

Take the absolute value of difference, where the absolute value can be as much as 5. Which gives the required inequality for the situation.

|s - 65| ≤ 5

Hence, the required inequality is |s - 65| ≤ 5.

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You are driving up a long inclined road. After 1.7 miles you notice that signs along the roadside indicate that your elevation h
kobusy [5.1K]

Answer:

θ = 3.38 degrees

r = 0.48mi

Explanation:

a) Start by converting 1.7 mi into feet.

1mile = 5280 feet,

so 1.7 mi = 8976 ft

y=rsin\theta,

so \theta = sin^{1] {530}{8976}

and θ = 3.38 degrees

b )Now to gain another 150 ft of elevation, again use the

equation y=rsin(θ)

150 = rsin(3.38)

r = 2544.187 ft.

Convert r = 2544.187 ft into miles by dividing by 5280,

and r = 0.48mi

4 0
3 years ago
Read 2 more answers
A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
icang [17]

Wave speed = (wavelength) x (frequency)

                       =      (4 m)        x  (2 /sec)

                       =               8 m/sec

7 0
4 years ago
Can you help and explain these for me?
ollegr [7]
Yes I can do you want me to
8 0
3 years ago
A ball of mass 0.600 kg is carefully balanced on a shelf that is 2.20 m above the ground. What is its gravitational potential en
katovenus [111]

Answer:

Explanation:

Gravitational potential energy = mass x height of object x g

g is gravitational acceleration .

Gravitational potential energy of the ball = .600 x 2.20 x 9.8

= 12.936 J .

12.9 J .

4 0
3 years ago
A Hooke's law bowstring is stretched x meters until a force of f newtons is applied, and then held. By what factor will the elas
Liono4ka [1.6K]

The elastic potential energy increases by a factor of 9

Explanation:

The elastic potential energy of a bowstring is given by

E=\frac{1}{2}kx^2 (1)

where

k is the spring constant

x is the elongation of the bowstring

Hooke's law states the relationship between the force applied and the elongation of an elastic object:

F=kx

where

F is the force applied

x is the elongation

We can rewrite it as

x=\frac{F}{k}

And substituting into (1),

E=\frac{1}{2}k(\frac{F}{k})^2=\frac{F^2}{2k}

In  this problem, the force applied to the bowstring is tripled,

F' = 3F

So the final elastic potential energy is:

E'=\frac{(3F)^2}{2k}=9(\frac{F^2}{2k})=9E

So, the elastic potential energy increases by a factor of 9.

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0
3 years ago
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