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Sophie [7]
2 years ago
5

Name the part of the eye that regulates the size of the passage through which light enters.

Physics
1 answer:
loris [4]2 years ago
7 0
The PUPIL regulates the size of the passage through which light enters.
You might be interested in
If a seismic wave has a period of 0.0202s, find the frequency of the wave.
maw [93]

Answer:

49.5 Hz.

Explanation:

From the question given above, the following data were obtained:

Period (T) = 0.0202 s

Frequency (f) =?

The frequency and period of a wave are related according to the following equation:

Frequency (f) = 1 / period (T)

f = 1/T

With the above formula, we can obtain the frequency of the wave as follow:

Period (T) = 0.0202 s

Frequency (f) =?

f = 1/T

f = 1/0.0202

f = 49.5 Hz

Therefore the frequency of the wave is 49.5 Hz.

7 0
3 years ago
What is the formula of gravity force with its meaning ​
tester [92]

Answer:

he formula for the gravitational force includes the gravitational constant, which has a value . The unit of the gravitational force is Newtons (N). Fg = gravitational force between two objects ( ) G = gravitational constant ( ) m1 = mass of the first object (kg)

Explanation:

brainlist ?

5 0
3 years ago
Excellent human jumpers can leap straight up to a height of
Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.  

We can calculate the initial speed to reach 110 cm of height with the following equation:

v_{f}^{2} = v_{i}^{2} - 2gh

Where:

v_{f}: is the final speed = 0 (at the maximum height of 110 cm)

v_{i}: is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the <u>initial velocity</u> is:

v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0
2 years ago
A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
nikitadnepr [17]

The radius of curvature of the proton's path while in the field is 66.67  × 10^{-2}.

b) Let R = radius curvature of protons path. Then,

relation b/w B, R, and v is: -

B = mv/eR\\R=mv/eB

R=\frac{1.6*10^{-27} * 20*10^{6}}{1.6*10^{-19}*0.3 }

R =66.67× 10^{-2}

Hence, the radius of curvature of the proton's path while in the field is 66.67 × 10^{-2}.

<h3>What do you mean by Magnetic field?</h3>

The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.  The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things.

To know more about Magnetic Field visit:

brainly.com/question/14848188

#SPJ4

5 0
1 year ago
Suppose an element had an atomic number of 52. How many protons would that element have?
frutty [35]
The element would have 52 protons because atomic number gives protons.
4 0
2 years ago
Read 2 more answers
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