Answer:
The field gets weaker
Explanation:
I’m taking the test right now, hope this helps!!
Answer:
<em>The two balls pass each other at a height of 5.53 m</em>
<em>vf1=17.97 m/s</em>
<em>vf2=-5.96 m/s</em>
Explanation:
<u>Vertical Motion</u>
An object thrown from the ground at speed vo, is at a height y given by:

Where t is the time and 
Furthermore, an object dropped from a certain height h will fall a distance y, given by:

Thus, the height of this object above the ground is:

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.
We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

Simplifying:

Solving for t:

The height of ball 1 is:

H = 5.53 m
The height of ball 2 is:

y=5.53 m
As required, both heights are the same.
The speed of the first ball is:

vf1=17.97 m/s
The speed of the second ball is:

vf2=-5.96 m/s
This means the second ball is returning to the ground when both balls meet
Answer:
B. less
Explanation:
acceleration due to gravity on Earth, g = 9.8 m/s²
acceleration due to gravity on Moon, g = 1.6 m/s²
Given mass of the object as, m = 5 kg
Weight of an object is given as, W = mg
Weight of the object on Earth, W = 5 x 9.8 = 49 N
Weight of the object on Moon, W = 5 x 1.6 = 8 N
Therefore, the object weighs less on the moon compared to its weight on Earth.
The correct option is "B. less"
GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N
<span>GPE=mgh=675(26000)=17.55x10^6J</span>
Answer:
A. Change that normally occurs in people throughout their lifetimes.
Explanation:
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