By analyzing the vector, the clothesline tension is 25 N.
We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as
F = (Fx i + Fy j) N
where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.
From the question we know that :
x = 10 m
(midpoint = 5m)
y = 1 m
m = 1 kg
Find the weight
W = m . g
W = 1 x 10
W = 10N
There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write
∑Fy = 0
Ty + Ty - W = 0
2Ty - 10 = 0
2Tsinθ - 10 = 0
Find sinθ
sinθ = y/x
sinθ = 1/5
Substitute the sinθ
2Tsinθ - 10 = 0
2T(1/5) - 10 = 0
2T/5 = 10
T = 25 N
Hence, the clothesline tension is 25 N.
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This problem can be solved by using oxidation states. The oxidation state is based on the electrons an atom loses or gain, or appears to use when forming compounds.To find the formula for Copper (I) Sulfide, we have to first consider the individual ions that come together to form it. Copper (I) is an ion of copper that has a charge of +1, i.e
. Sulfur is an element in group 6 of the periodic table. The sulfur ion has a charge of -2, i.e
. To form Copper (I) Sulfide, which is electrically neutral, we need 2 Copper (I) ions and 1 sulfur ion.
.
The reaction is represented by the equation below
.
The correct answer is (C)
The answer would be reflected.
Answer:
a) 1/4 what it is now
Explanation:
As we know that force of gravitation between two planets at some distance "r" from each other is given as

now since we know that if the distance between Earth and Sun is changed
So the force of gravity will be given as

now we know that the distance between sun and earth is changed to twice the initial distance between them
so we have

so new gravitational force between sun and earth is given as


119.7kPa
Explanation:
Given parameters:
Pressure of gas in balloon = 111kPa
Temperature of gas = 22°C
Final temperature = 45°C
Unknown:
Final pressure = ?
Solution:
Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.
At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.

P1 is the initial pressure
P2 is the final pressure
T1 is the initial temperature
T2 is the final temperature
convert from celcius to kelvin:
tK = 273 + tC
T1 = 273 + 22 = 295K
T2 = 273 + 45 = 318K

P2 = 119.7kPa
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