What a delightful little problem !
Here's how I see it:
When 'C' is touched to 'A', charge flows to 'C' until the two of them are equally charged. So now, 'A' has half of its original charge, and 'C' has the other half.
Then, when 'C' is touched to 'B', charge flows to it until the two of <u>them</u> are equally charged. How much is that ? Well, just before they touch, 'C' has half of an original charge, and 'B' has a full one, so 1/4 of an original charge flows from 'B' to 'C', and then each of them has 3/4 of an original charge.
To review what we have now: 'A' has 1/2 of its original charge, and 'B' has 3/4 of it.
The force between any two charges is:
F = (a constant) x (one charge) x (the other one) / (the distance between them)².
For 'A' and 'B', the distance doesn't change, so we can leave that out of our formula.
The original force between them was 3 = (some constant) x (1 charge) x (1 charge).
The new force between them is F = (the same constant) x (1/2) x (3/4) .
Divide the first equation by the second one, and you have a proportion:
3 / F = 1 / ( 1/2 x 3/4 )
Cross-multiply this proportion:
3 (1/2 x 3/4) = F
F = 3/2 x 3/4 = 9/8 = <em>1.125 newton</em>.
That's my story, and I'm sticking to it.
Answer:
minimum initial velocity is 21.35 m/s
Explanation:
given data
distance S = 30 m
height h = 30 m
maximum acceleration a = 2 m/s²
to find out
minimum initial velocity that your friend could have thrown the object to enable you to catch
solution
first we get here time with the help of second equation of motion
time = 
..................1
put her value we get
time = 
time = 5.477 second
and that is time which tossed object must be take so we apply here again second equation of motion that is
-S = ut - 0.5 × gt² .......................2
-30 = u× 5.477 - 0.5 ×9.8×5.477²
solve it we get
u = 21.35 m/s
so minimum initial velocity is 21.35 m/s
The distance between two consecutive compressions or rarefactions in a wave is called wavelength.
Answer:
The value of heat transfer during the process Q = - 29.49 KJ
Explanation:
Given data
= 50 
= 344.7 k pa
= 0.113 
F = 366.4 K
= 477.6 K
Poly tropic index n = 1.2
gas constant for oxygen = 0.26 
From ideal gas equation
= m R 
Put all the values in above equation we get
⇒ 344.7 × 0.113 = m × 0.26 × 366.4
⇒ m = 0.408 kg
Heat transfer in poly tropic process is given by
Q = ![\frac{\gamma - n}{( \gamma - 1)( n - 1)} [ {m R (T_{1} - T_{2} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cgamma%20-%20n%7D%7B%28%20%5Cgamma%20-%201%29%28%20n%20-%201%29%7D%20%5B%20%7Bm%20R%20%28T_%7B1%7D%20-%20T_%7B2%7D%20%20%29%20%5D)
Put all the values in above formula we get
⇒ Q = ![\frac{1.4 - 1.2}{( 1.4 - 1)( 1.2 - 1)} [ {m R (T_{1} - T_{2} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B1.4%20-%201.2%7D%7B%28%201.4%20-%201%29%28%201.2%20-%201%29%7D%20%5B%20%7Bm%20R%20%28T_%7B1%7D%20-%20T_%7B2%7D%20%20%29%20%5D)
⇒ Q = 2.5 × 0.408 × 0.26 × ( 366.4 - 477.6 )
⇒ Q = - 29.49 KJ
This is the value of heat transfer during the process & negative sign shows that heat is lost during the process.
Answer: 780080
Explanation: BY FORMULA OF K.E
K.E= 1/2 MV^2
= 1/2 (1990)(28)^2
= 780080 JOULE
