How are the surface of Mercury and Mars similar to the surface of the Earth?

Physics

1 answer:

scZoUnD [109]3 years ago

8 0

Answer:

The terrestrial planets all have rocky surfaces that feature mountains, plains, valleys and other formations. ... Mars has very low atmospheric pressure, and Mercury has almost none, so craters are more common on these planets.

Explanation:

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Plz explain the answers with steps and a little bit of explanation. I really need the answers for my exam tomorrow! Please help

DochEvi [55]

Here's what you need to memorize for your exam tomorrow.

Distance = (speed) x (time) .

That's it. Memorize it.

-- If the question wants you to find speed, use it exactly in that form.

-- If the question wants you to find speed, then divide each side by (time)
and it says

. Time = (distance) / (speed) .

-- If the question wants you to find time, then divide each side by speed,
and it says

. Time = (distance) / (speed) .

So if you memorize that one equation ... Distance = (speed) x (time) ...
you can solve ANY problem to find distance, speed, or time.

On the sheet in the picture . . . . .

#2). The question is "How long ?". That's TIME that you have to find.
Use the equation in the form of

. TIME = (distance) / (speed)

. = (60 km) / (48 km/h)

. = 1.25 hours .

#3). This one wants you to find SPEED. Use the equation in the form of

. SPEED = (distance) / (time)

but be careful. The time has to be in hours. 55 minutes = 55/60 of an hour.

. SPEED = (distance) / (time)

. = (60 km) / (55/60 hour)

. = (60 x 60 km) / (55 hour)

. = 65.45 km/hr .

#4). This one wants you to find TIME. (It says "How long ?".)

It's two trips, so you have to find the time for each trip.

First trip: TIME = (distance)/(speed) = (24 km)/(65 km/hr) = 0.369 hr

Second trip: TIME = (distance)/(speed) = (50 km)/(80 km/hr) = 0.625 hr

Total time for both trips = (0.369 hr) + (0.625 hr) = 0.994 hour

7 0

3 years ago

a 2kg object is moving horizontally with a speed of 4 m/s.how much net force is required to keep the object moving at this speed

Elza [17]

If the object is moving in a straight line with constant speed,
that's a description of " acceleration = zero ".

Zero acceleration means zero net force on the object.

NO net force is 'required' to keep an object moving in a straight line
at constant speed. In fact, if there IS any net force on the object,
then either its speed or its direction MUST change ... there's no way
to avoid it.

None of this depends on the object's mass, or on the speed or direction
of its motion.

8 0

3 years ago

(a) The stick is supported by a sharp point at the middle. On the left side, a weight of 100 g is suspended at 40 cm from the mi

Jet001 [13]

Answer:

20cm

Explanation:

Hello!

remember that the condition for a body to be at rest is that the sum of its moments and its forces be zero,

To solve this problem you must draw the free body diagram of the stick (attached image) and sum up moments at point 0 (where the sharp is located), which results in the following equation

(100g)(40cm)=x(200g)

$X=\frac{(100)(40)}{(200)} =20cm$