Answer:
Explanation:
The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted).
Change in velocity = d(v)
d(v) = v2 - v1 where v1 = initial speed, v2 = final speed
v1 = 28.0 m/s to the right
v2 = 0.00 m/s
d(v) = (0 - 28)m/s = -28 m/s to the right
Change in time = d(t)
d(t) = t2 - t1 where t1 = initial elapsed time, t2 = final elapsed time
t1 = 0.00 s
t2 = 5.00 s
d(t) = (5.00 - 0.00)s = 5.00s
Average acceleration = d(v) / d(t)
(-28.0 m/s) / (5.00 s)
(-28.0 m)/s * 1 / (5.00 s) = -5.60 m/s² to the right
Answer:
1) Determine the domain of the following functions: d ... 3) If g(x) = x + 3 and f(x)= x² – 2x, find the value of f(g(a)). ... 6) Given the graph of f(x) to the right, determine: ... 8) Given f(x)= x? and g(x)= 2* The inverse of g is a function, but the inverse off is ... -3(x-1)= -5 4 (-3). -3x+ 3 = y. 10) The graph of a function f (x) is given at the.
Explanation:
Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m
Answer:
See the explanation below.
Explanation:
Indeed this is a serial circuit, in order to calculate the different questions, we must calculate the current of the circuit. The total resistance of the circuit can be calculated by means of an algebraic summation.
Then using ohm's law,we can calculate the current.
Rt = 2 + 4 + 6 = 12 [ohm]
The current
I = V / Rt
I = 12 / 12
I = 1 [amp]
Therefore the voltage in each resistance will be:
V1 = 2 * 1 = 2 [V]
V2 = 4 * 1 = 4 [V]
V3 = 6 * 1 = 6 [V]
The total voltage will be:
V = V1 + V2 + V3 = 12 [V]
The power can be calculated by multiplying the voltage by the total current.
P = V * I
P = 12 * 1
P = 12 [W]
